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06 Apr 2018, 05:13
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If x is an integer, then the least possible value of |33−x^2| is
A. 0
B. 3
C. 5
D. 6
E. 8
A. 0
B. 3
C. 5
D. 6
E. 8
06 Apr 2018, 08:30
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As absolute value is always non negative,
we have to find x such that its square is close to 33
if x = 6, x^2 = 36
here |33−x^2| = 3, this is the least value. Answer B
( if the restriction on x to be integer not there , least value would be 0, when x = root 33 )
we have to find x such that its square is close to 33
if x = 6, x^2 = 36
here |33−x^2| = 3, this is the least value. Answer B
( if the restriction on x to be integer not there , least value would be 0, when x = root 33 )
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09 Apr 2018, 11:02
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For it to have a least possible value, you need to consider the modulus . 6^2 gives 36 which when subtracted by 33 gives 3 thereby providing with 3 as the least possible value.
Answer B
Answer B
