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CLIMBTHELADDER
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The table above shows the number of employees at each of four salary Updated on: 22 Apr 2018, 02:38
Originally posted by CLIMBTHELADDER on 22 Apr 2018, 02:33.
Last edited by Bunuel on 22 Apr 2018, 02:38, edited 1 time in total.
Renamed the topic and edited the question.
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91% (01:30) correct 9% (01:35) wrong based on 906 sessions

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The table above shows the number of employees at each of four salary levels at Company X. What is the average (arithmetic mean) salary for the 20 employees?

A. $23,500
B. $23,750
C. $23,900
D. $24,125
E. $24,250

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C
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The table above shows the number of employees at each of four salary 22 Apr 2018, 02:50
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IRONMANGMAT

The table above shows the number of employees at each of four salary levels at Company X. What is the average (arithmetic mean) salary for the 20 employees?

A. $23,500
B. $23,750
C. $23,900
D. $24,125
E. $24,250

Show Spoiler
Attachment:
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weighted average problem

avg = \(\frac{(20000*5 + 22000*4 + 25000*8 + 30000*3)}{20}\) = 23900

ans C
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The table above shows the number of employees at each of four salary 22 Apr 2018, 04:04
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Remove zeros and add them later

Av=20*5 +22*4 +8*25 +30*3 /20
=23.9 multiply by 1000 =23900

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The table above shows the number of employees at each of four salary 16 Aug 2018, 01:49
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Hi,
Simply assume that all get 20,000 then the average would have been 20,000.
Now 4 people get 2000 more than average, 8 people get 5000 more than average, 3 people get 10000 more than average
the total would be (4*2000)+(8*5000)+(3*10000)=78000
And this additional 78000 would be divided equally among 20 people

newavg= 20,000+(78000/20)
=20,000+3900
=23,900

Hence Option C

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The table above shows the number of employees at each of four salary 07 Oct 2020, 03:33
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OFFICIAL GMAT EXPLANATION

From the table, there are 5 employees each with a salary of $20,000, 4 employees each with a salary of $22,000, and so on. The average (arithmetic mean) for all 20 employees is then:

5(20,000) + 4(22,000) +8(25,000) + 3(30,000)
______________________________________
20

= 100,000 + 88,000 + 200,000 + 90,000
____________________________________
20

= 478,000
________
20

= 23,900
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The table above shows the number of employees at each of four salary 26 May 2021, 11:36
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Average= (100000+88,000+200,000+90,000)/20
= 23900 (C)
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The table above shows the number of employees at each of four salary 07 Mar 2025, 19:32
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