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30 Jun 2018, 23:53
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
61% (01:25) correct
39%
(01:30)
wrong
based on 1318
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Which of the following is closest to the value of \((\sqrt{21}-\sqrt{7})^2\)?
A. 4
B. 5
C. 7
D. 16
E. 196
A. 4
B. 5
C. 7
D. 16
E. 196
01 Jul 2018, 00:07
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this is of the form a2-2ab+b2
so we have (sqrt21)^2 - 2 sqrt(21*7) + sqrt7^2
= 21 - 2(sqrt 147) + 7
=28- 2 (sumthin more little more than 12) as 12 sqare is 144
=28-24 = 4 , now ans should be littler less than 4 as we have srt 147 , which is little more than 12
so ans 3
so we have (sqrt21)^2 - 2 sqrt(21*7) + sqrt7^2
= 21 - 2(sqrt 147) + 7
=28- 2 (sumthin more little more than 12) as 12 sqare is 144
=28-24 = 4 , now ans should be littler less than 4 as we have srt 147 , which is little more than 12
so ans 3
01 Jul 2018, 02:43
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Bunuel
21 lies between \(16(4^2)\) and \(25(5^2)\) and the square root of 21 is little over 4.5 \((4.5^2 = 20.25)\)
Similarly, 7 lies between \(4(2^2)\) and \(9(3^2)\) and the square root of 7 is a little over 2.6 \((2.6^2 = 6.76)\)
Therefore, the value closest to \((\sqrt{21}-\sqrt{7})^2\) is \((4.5 - 2.6)^2 = (1.9)^2\) = approximately 4(Option A)
