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13 Nov 2018, 00:34
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
71% (01:15) correct
29%
(01:45)
wrong
based on 94
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In the figure above, square ABCD has an area of 25. What is the area of the circle with center O ?
A. \(\frac{5\sqrt{2}\pi}{2}\)
B. \(\frac{25\pi}{4}\)
C. \(\frac{25\pi}{2}\)
D. \(5\sqrt{2}\pi\)
E. \(25\pi\)
Attachment:
2018-11-13_1131.png [ 32.35 KiB | Viewed 2804 times ]
Updated on: 13 Nov 2018, 01:15
Originally posted by GMATinsight on 13 Nov 2018, 00:57.
Last edited by GMATinsight on 13 Nov 2018, 01:15, edited 2 times in total.
Last edited by GMATinsight on 13 Nov 2018, 01:15, edited 2 times in total.
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Bunuel
Area of square \(= a^2 = 25\) where a is the side of the square
i.e. Side of the square, \(a = 5\)
But Diagonal of the square = Diameter of the circle
and Diagonal of the square with side a \(= a√2\)
i.e. Diameter of teh circle \(= 5√2\)
Area of the circle \(= (π/4)d^2\) where d is the diameter of the circle
i.e. Area of the circle \(= (π/4)(5√2)^2 = 12.5π\)
Answer: Option C
