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Kinshook
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Since the slope of the line is 2 and for a line to be perpendicular to the other line we know that product of their slopes must equal -1

m1*m2=-1
so we are looking for a line with slope -1/2

Two ways you have:

2 point line equation:

y-7= -1/2*(x-1)
2y-14= 1-x
2y+x=15

or its simple to see that only A and B have the required slope but only A fits the coordinates.
Plugging in the numbers is quicker

Answer A
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Kinshook
If a line L has slope 2 and has y-intercept 5, then what is the equation of line perpendicular to line L and passing through point (1,7)?

A. 2y+x =15
B. 2y+x = 10
C. y=2x+5
D. y=2x-13
E. y+2x=9

Slope of perpendicular line m1*m2=-1 So 2*m2= -1 implies m2=-1/2


Now we need to save time so lets directly jump to options and see which equation of line has slope =-1/2 and passes through point (1,7)

In y=mx+c m is slope .

Option C,D,E remove as slope is 2 there.Now lets see A and B options.

Option A:
y= -x/2 + 15/2
Slope =-1/2

Similarly option B

y= -x/2 + 5

Now we know perpendicular passes through (1,7)

Only option A satisfies above equation.

So option A.


Hope it helps!!
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