A salesperson who had been driving at a speed of 100 kilometers per ho

Question

A salesperson who had been driving at a speed of 100 kilometers per hour slowed down to a speed of 47 kilometers per hour. Approximately how many miles per hour was the speed reduced?
 (1 kilometer ≈ 0.625 mile)

A. 29
B. 33
C. 53
D. 63
E. 75

PS92820.02

chetan2u · Accepted Answer

Now, the speed reduced by 100-47=53kmph... All you have to do is convert 53 km into miles, so 53*0.625. Now 53*0.625>50*0.6 or >30...Eliminate A 53*0.625<53*1 or <53....Eliminate C, D and E Answer B

BrentGMATPrepNow · Answer

A salesperson who had been driving at a speed of 100 kilometers per hour slowed down to a speed of 47 kilometers per hour.  
Reduction in speed = 100 - 47 =  53  kilometers per hour
We can use  equivalent ratios  to convert  53  kilometers per hour to miles per hour.

We are told that 1 kilometer ≈ 0.625 miles

So, if we use the ratio  kilometers / miles , we can express the relationship as:  kilometers / miles  =  1 / 0.625 
Let  x  = the desired speed (in mph)
We can now write:  1 / 0.625  =  53 / x 
Cross multiply to get: 1x = (53)(0.625) ≈ 33 mph

Answer: B

Cheers,
Brent
RELATED VIDEO
 https://www.youtube.com/watch?v=Yegch7sv6MY

Archit3110 · Answer

net change in speed ; ( 100-47) ; 53 kmph
1 km = .625 miles
so in 1 hour distance ; 53 kmph or say 55 *.625 ; 33 miles 
OPTION B

Kritisood · Answer

Bunuel  is there a tag specifically to practice such conversion questions? 2021OG seems to have a quite few of this type.

Bunuel · Answer

No tag. Check other  Conversion problems  to practice in  Special Questions Directory .

perfectreview · Answer

Difference between the speeds is 100kmpd - 47kmph = 53kmph ≈ 50kmph

1 kilometer ≈ 0.625 mile ≈ 0.6 mlie

Speed in miles per hour ≈ 50*0.6 ≈ 30

Answer has to be slightly greater than 30

Therefore answer is  Option B

MHIKER · Answer

Reduced kilometers =100-47=53

Reduced miles  =53*0.625=50*0.7<35 \ and \ 50*0.60>30=33

The answer is B

CrackverbalGMAT · Answer

b]SOLUTION:

This is a conversion problem.

Initial speed = 100 kmph

Final Speed = 47 kmph

Reduction = 100 - 47 =53 kmph and as 1kmph =0.625 miles(given),

53 kmph = 53 x (625/1000) = 53 x 5/8 = 265/8 = 33.125 mph

= 33mph(approx.) OPTION B

Hope this helps

Devmitra Sen(Math)

GMATinsight · Answer

Answer: Option B

Video solution by  GMATinsight

https://www.youtube.com/watch?v=B4iWPxU0rWM

avigutman · Answer

Video solution from Quant Reasoning starts at 3:27 Subscribe for more: https://www.youtube.com/QuantReasoning? ... irmation=1 https://www.youtube.com/watch?v=f1ZUcAczAF8

Jainam24 · Answer

Reduction in speed = 100 - 47 = 53 kmph 
One has to convert 53 km into miles. Why? 
Because the question asks per hour.

So 53*0.625 will give the ans. C, D and E options are out. 
The most important word in the question was "approximate"
So we can approximate 0.625 to 0.6 and check. Whatever ans we get is slightly lesser than the actual value(since are multplier has reduced by 0.025)
So 53*6/10= 318/10=31.8 
Thus B is the ans

ArnauG · Answer

he salesperson's initial speed was 100 kilometers per hour. To convert this to miles per hour, we use the conversion factor of 0.625 miles per kilometer:

Initial speed in miles per hour = 100 km/h * 0.625 miles/kilometer = 62.5 miles per hour

The salesperson's reduced speed was 47 kilometers per hour. Converting this to miles per hour:

Reduced speed in miles per hour = 47 km/h * 0.625 miles/kilometer = 29.375 miles per hour

To find the reduction in speed, we subtract the reduced speed from the initial speed:

Reduction in speed = 62.5 miles per hour - 29.375 miles per hour = 33.125 miles per hour

Rounding this to the nearest whole number, we find that the speed was reduced by approximately 33 miles per hour

bumpbot · Answer

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A salesperson who had been driving at a speed of 100 kilometers per ho

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