How far is the point (–3, –4) from the origin?

Question

(A) 2

(B) 2.5

(C) 5

(D)  4 \sqrt{2}

(E)  4 \sqrt{3}

alwaysHP · Answer

Formula =\sqrt{(-3-0)^2+(-4-0)^2} = 5

shverma · Answer

Since we know that we have to find the distance, we can neglect the signs and consider only the magnitudes. 
Hence, (-3) will represent the distance of magnitude 3 from the origin on the X-axis.
Similarly, (-4) will represent the distance of magnitude 4 from the origin on the Y-axis.

Therefore, the distance from the origin will be equal to the diagonal of the rectangle formed with one of its edge at the origin and the opposite one at point (-3,-4).
Also, the diagonal can be calculated with the Pythagoras theorem (similar to finding the hypotenuse of a right-angled triangle).
=> Distance = \sqrt{ 3^2 + 4^2 }= 5

Abhishek009 · Answer

\sqrt{|4|^2 + |3|^2} = 5 , Answer must be (C)

sumisachan · Answer

Distance Formula =  \sqrt{ ^2 +  ^2}

\sqrt{ ^2 +  ^2}  = 5.

jhavyom · Answer

(X1,Y1) = (0,0)
(X2,Y2) = (-3,-4)

Distance = \sqrt{(X2-X1)^2 + (Y2-Y1)^2}
= \sqrt{(-3-0)^2 + (-4-0)^2}
=\sqrt{9+16}
=\sqrt{25}
=5
   Posted from my mobile device

MathRevolution · Answer

Let O(0,0) and A(-3, -4)

=> OA =  \sqrt{(-3-0)^2 + (-4-0)^2}

=> OA =  \sqrt{9 + 16} = \sqrt{25}

=> OA = 5

Answer C

Sr1994 · Answer

If we want to find the distance from origin, we can use the equation  \sqrt{X^2 + Y^2}

(-3,-4)

=  \sqrt{(-3)^2+(-4)^2} 
=  \sqrt{9+16} 
=  \sqrt{25} 
= 5

Answer C

How far is the point (–3, –4) from the origin?

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How far is the point (–3, –4) from the origin?

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