An Electrical Engineering website requires users to create a password

Question

An Electrical Engineering website requires users to create a password using letters from the word MAGNET. If each password must have at least 4 letters and no repeated letters are allowed, how many different passwords are possible?

A. 360

B. 720

C. 1080

D. 1440

E. 1800

A. 360
B. 720
C. 1080
D. 1440
E. 1800

PrashantK0099 · Answer

MAGNET

A password consisting of 4 letters: 6*5*4*3 = 360.

A password consisting of 5 letters: 6*5*4*3*2 = 720.

A password consisting of 6 letters 6*5*4*3*2*1 = 720.

Total Ways = 360+720+720=1800

Hence E

Yousuf2752 · Answer

In the word MAGNET, there is no repetition of any of the letters.

So, 
6 letters can be arranged for 6 positions in 6! ways
6 letters can be arranged for 5 positions in 6! ways 
6 letters can be arranged for 4 positions in 6!/2! ways

Total possible combinations = 6!+6!+ 6!/2! ways
=720+720+360
= 1800 ways

EgmatQuantExpert · Answer

Given

• An Electrical Engineering website requires users to create a password using letters from the word MAGNET. 
• Each password must have at least 4 letters and no repeated letters are allowed.

To Find

• The number of different passwords are possible

Approach and Working Out

• Number of letter can be 4, 5, or 6.
 o The number of 4-letter passwords = 6P4 = 360
o The number of 5-letter passwords = 6P5 = 720
o The number of 6-letter passwords = 6P6 = 720

• Total number = 360 + 720 + 720 = 1800.

Correct Answer: Option E

exc4libur · Answer

magnet=6letters
pass >= 4 letters
4L: prod(6,5,4,3)=360
5L: prod(6,5,4,3,2)=720
6L: 6!=720
total: 1800

Ans (E)

MathRevolution · Answer

MAGNET: Total letters '6'

Atleast 4 letters: 4 letters + 5 letters + 6 letters

4 letters password: _ _ _ _: 1st space has 6 choices, 2nd space has 5 choices, and so on: 6 * 5 * 4 * 3 = 360

5 letters password: _ _ _ _: 1st space has 6 choices, 2nd space has 5 choices, and so on: 6 * 5 * 4 * 3 * 2 = 720

6 letters password: _ _ _ _: 1st space has 6 choices, 2nd space has 5 choices, and so on: 6 * 5 * 4 * 3 * 2 * 1 = 720

Total: 360 + 720 + 720 = 1800

Answer E

akadiyan · Answer

Requirement :
To create password using the word MAGNET

Restrictions :
Password must have atleast 4 letters
No repeated letters allowed

Solution 
Since password must have atleast 4 letters, the possible lengths are 4, 5 and 6

Lets use permutation in this case. The formula to calculate permutation is  \frac{n! }{ (n-r)!}

The number of possibilities for a 4 letter password is  \frac{6! }{ (6-4)!}  = 360
The number of possibilities for a 5 letter password is  \frac{6! }{ (6-5)!}  = 720
The number of possibilities for a 6 letter password is  \frac{6! }{ (6-6)!}  = 720

Total combination is 360+720+720 = 1800

Ans:   E

SairamRamo · Answer

MAGNET has 6 different letters

No of Password with length 4 ; 6p4
No of Password with length 5 : 6p5
No of Password with length 6 : 6!

Total = 6p4 + 6p5 + 6! = 1800

IMO E

alwaysHP · Answer

MAGNET
 4-letter passwords = 6P4 = 360
5-letter passwords = 6P5 = 720
6-letter passwords = 6P6 = 720

Total=360+720 +720 = 1800.

ScottTargetTestPrep · Answer

Solution:

The number of 4-, 5-, and 6-letter passwords that can be formed using the word MAGNET (with no letters repeated) are 6P4, 6P5 and 6P6, respectively. Therefore, the total number of different passwords that can be formed is:

6P4 + 6P5 + 6P6 = (6 x 5 x 4 x 3) + (6 x 5 x 4 x 3 x 2) + 6! = 360 + 720 + 720 = 1800

Answer: E

An Electrical Engineering website requires users to create a password

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