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03 Dec 2020, 12:00
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
92% (00:32) correct
8%
(00:50)
wrong
based on 38
sessions
History
Date
Time
Result
Not Attempted Yet
Find the perimeter of a square whose diagonal is \(6 \sqrt{2 }\).
(A) \(24 \sqrt{2}\)
(B) 24
(C) 20
(D) \(12 \sqrt{2}\)
(E) 12
(A) \(24 \sqrt{2}\)
(B) 24
(C) 20
(D) \(12 \sqrt{2}\)
(E) 12
ananya3
Current Student
Joined: 05 Oct 2018
Last visit: 17 Dec 2022
Posts: 106
Given Kudos: 152
Location: India
Schools: Fuqua '24 Haas '24 ISB '23 Johnson '24 Kelley '24 Kenan-Flagler '24 McDonough '24 NUS Ross '24 Tepper '24 Tuck '24 Rotman '24 (A)
GMAT 1: 700 Q49 V36
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Schools: Fuqua '24 Haas '24 ISB '23 Johnson '24 Kelley '24 Kenan-Flagler '24 McDonough '24 NUS Ross '24 Tepper '24 Tuck '24 Rotman '24 (A)
GMAT 1: 700 Q49 V36
Posts: 106
03 Dec 2020, 19:53
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IMO B
Diagonal of a square = √2 * side of square
(we can also think the triangle formed by two adjacent sides of the square and the diagonal as an isosceles right angle triangle where the sides are in the ratio: side:side:hypoteneus = 1:1:√2)
=> 6√2 = √2*side
=> side = 6
perimeter = 6*4 = 24
Diagonal of a square = √2 * side of square
(we can also think the triangle formed by two adjacent sides of the square and the diagonal as an isosceles right angle triangle where the sides are in the ratio: side:side:hypoteneus = 1:1:√2)
=> 6√2 = √2*side
=> side = 6
perimeter = 6*4 = 24
04 Dec 2020, 01:09
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CONCEPT:-Mensuration
-Let the side of the square be "a"
-Then the Perimeter = 4a
-Diagonal of the square=√2a
SOLUTION : With diagonal 6√2 units,we can equate
√2a =√2*6
=>a=6
=>Perimeter 4a=4*6=24 units(B)
Hope this helps
Devmitra Sen
-Let the side of the square be "a"
-Then the Perimeter = 4a
-Diagonal of the square=√2a
SOLUTION : With diagonal 6√2 units,we can equate
√2a =√2*6
=>a=6
=>Perimeter 4a=4*6=24 units(B)
Hope this helps
Devmitra Sen
