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A milk vendor has 2 cans of milk .The first contains 25% water and the 10 Dec 2020, 07:15
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A milk vendor has 2 cans of milk .The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the container so as to get 12 litres of milk such that the ratio of water to milk is 3:5?

A. 1 litres

B. 6 litres

C. 7 litres

D. 8 litres

D. 9 litres
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B
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A milk vendor has 2 cans of milk .The first contains 25% water and the 10 Dec 2020, 08:10
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ans is 6 litres ,since resultant mix % of water comes out as 37.5 % which is midway between container 1 and container 2 milk mixture . so the 2 mix are mixed in equal proportions . so out of 12 lit mixture - 6 of each container 1 and 2

ans is b
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A milk vendor has 2 cans of milk .The first contains 25% water and the 18 Jun 2023, 11:05
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Can someone give an explanation for this question?
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A milk vendor has 2 cans of milk .The first contains 25% water and the 20 Jun 2023, 22:07
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bajpaispandy
Can someone give an explanation for this question?
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Let x and (12-x) litres of milk be mixed from the first and second container respectively
Amount of milk in x litres of the the first container = \(3x/4\)
Amount of water in x litres of the the first container = \(x/4\)
Amount of milk in (12-x) litres of the the second container = \(\frac{1}{2}*(12-x)\)
Amount of water in (12-x) litres of the the second container = \(\frac{1}{2}*(12-x)\)

Ratio of water to milk = \(\frac{x}{4}\) + \(\frac{1}{2}*(12-x)\) : \(\frac{3x}{4}\) + \(\frac{1}{2}*(12-x)\) = 3 : 5

Solving this equation, we get x = 6
Hence 6 and 6 litres of milk should mixed from the first and second container respectively

Option B.
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A milk vendor has 2 cans of milk .The first contains 25% water and the 01 Jul 2023, 08:04
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Actually, if you read carefully, the question asks "how much milk should he mix from EACH container". Therefore, 12 = 2x; x=6
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A milk vendor has 2 cans of milk .The first contains 25% water and the 08 Sep 2024, 05:52
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