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Can someone give an explanation for this question?
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Can someone give an explanation for this question?

Let x and (12-x) litres of milk be mixed from the first and second container respectively
Amount of milk in x litres of the the first container = \(3x/4\)
Amount of water in x litres of the the first container = \(x/4\)
Amount of milk in (12-x) litres of the the second container = \(\frac{1}{2}*(12-x)\)
Amount of water in (12-x) litres of the the second container = \(\frac{1}{2}*(12-x)\)

Ratio of water to milk = \(\frac{x}{4}\) + \(\frac{1}{2}*(12-x)\) : \(\frac{3x}{4}\) + \(\frac{1}{2}*(12-x)\) = 3 : 5

Solving this equation, we get x = 6
Hence 6 and 6 litres of milk should mixed from the first and second container respectively

Option B.
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A simpler method, at least as per me.

We want 12 liters of milk where ratio of milk is to water is 3:5 i.e. milk will constitute 37.5% (3/8) of the total mixture.

Notice how 37.5% sits bang at the center of the milk content of the 2 containers - 25 & 50. Therefore, to get to 37.5% we will need to mix from both containers in equal proportion.

Now since we need 12 ltrs total mixture, 6 from each is the answer (Option B)
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