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Bunuel
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ID codes issued by XYZ high school have 5 characters. First 2 characte 05 Jan 2021, 00:25
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C
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61% (01:31) correct 39% (01:52) wrong based on 247 sessions

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ID codes issued by XYZ high school have 5 characters. First 2 characters of the ID codes are vowels and next 3 characters are digits. If ID code of no two students is same, then what is the maximum number of students in XYZ high school?

A. 12,500
B. 14,400
C. 25,000
D. 144,000
E. 250,000
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C
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ID codes issued by XYZ high school have 5 characters. First 2 characte 05 Jan 2021, 00:47
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Bunuel
ID codes issued by XYZ high school have 5 characters. First 2 characters of the ID codes are vowels and next 3 characters are digits. If ID code of no two students is same, then what is the maximum number of students in XYZ high school?

A. 12,500
B. 14,400
C. 25,000
D. 144,000
E. 250,000
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Since a digit or a vowel can repeat itself and ID code would still be a unique code, following exists
Ways to chose 2 vowels = 5*5
Ways to chose 3 digits = 10*10*10

Total number of ID Codes(students) = 25*1000
= 25000

Answer C.
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ID codes issued by XYZ high school have 5 characters. First 2 characte 05 Jan 2021, 11:03
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IMO its C . 25000 .

five vowels can be used in two positions 5x5
10 digits can be used at three positions 10x10x10

= 25000.


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ID codes issued by XYZ high school have 5 characters. First 2 characte 05 Jan 2021, 12:47
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Bunuel
ID codes issued by XYZ high school have 5 characters. First 2 characters of the ID codes are vowels and next 3 characters are digits. If ID code of no two students is same, then what is the maximum number of students in XYZ high school?

A. 12,500
B. 14,400
C. 25,000
D. 144,000
E. 250,000
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Basically, this is a problem of counting (repetition allowed).

_ _ _ _ _ = five character code.

1st and 2nd character - vowels - A, E, I, O, and U - 5 possibilities.
3rd, 4th and 5th character digits - 0,1,2,3,4,5,6,7,8,9 - 10 possibilities.

Therefore, total number of characters = 5x5x10x10x10 = 25000.

Answer C.
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ID codes issued by XYZ high school have 5 characters. First 2 characte 15 Sep 2022, 09:45
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In the question it is mentioned, no two IDs should be same

Am confused why repetition is allowed in this case.

For example:

_ _ _ _ _ can take a,a,1,1,1

This can be arranged in only one way and even if it is re arranged, the code would be same.

Can someone throw some light on this...
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ID codes issued by XYZ high school have 5 characters. First 2 characte 17 Sep 2022, 11:23
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santhosh1797
In the question it is mentioned, no two IDs should be same

Am confused why repetition is allowed in this case.

For example:

_ _ _ _ _ can take a,a,1,1,1

This can be arranged in only one way and even if it is re arranged, the code would be same.

Can someone throw some light on this...
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The question says that ID codes of no two students should be same and nothing regarding repetition of vowels or digits.

So students can have ID codes such as AA111 or EE555 or II999 and still their ID codes will not be same.

So, in disguise, the ques is asking - how many such unique ID codes (which doesn't mean unique letters) are possible in total?

which is 5 * 5 * 10 * 10 * 10 = 25000
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ID codes issued by XYZ high school have 5 characters. First 2 characte 11 Oct 2023, 04:34
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Given: ID codes issued by XYZ high school have 5 characters. First 2 characters of the ID codes are vowels and next 3 characters are digits.

Asked: If ID code of no two students is same, then what is the maximum number of students in XYZ high school?

Total number of ID cards = Maximum number of students = 5*5*10*10*10 = 25000

IMO C
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ID codes issued by XYZ high school have 5 characters. First 2 characte 25 Jun 2025, 02:20
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