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Bunuel
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GMAT 2: 760 Q51 V40
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How did you get the denominator as 2?
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Hi, can someone please explain how the denominator is 2?
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Bunuel
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Oh! Thank you so much! For some reason I thought it was 16 x 1/4 and was confused :dazed

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Bunuel
What is the value of \(\frac{\sqrt[3]{64} + 3^3}{(16)^{\frac{1}{4}}}\) ?

A. 17/4

B. 31/4

C. 17/2

D. 35/4

E. 31/2
\(\frac{\sqrt[3]{64} + 3^3}{(16)^{\frac{1}{4}}}\)

= \(\frac{\sqrt[3]{4^3} + 3^3}{(2^4)^{\frac{1}{4}}}\)

= \(\frac{{4} + 3^3}{2}\)

= \(\frac{{31}}{2}\), Answer will be (E)
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