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04 Jun 2021, 08:45
Kudos
Bookmarks
E
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Difficulty:
5%
(low)
Question Stats:
89% (00:43) correct
11%
(00:58)
wrong
based on 111
sessions
History
Date
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Not Attempted Yet
What is the value of \(\frac{\sqrt[3]{64} + 3^3}{(16)^{\frac{1}{4}}}\) ?
A. 17/4
B. 31/4
C. 17/2
D. 35/4
E. 31/2
A. 17/4
B. 31/4
C. 17/2
D. 35/4
E. 31/2
04 Jun 2021, 13:41
Kudos
Bookmarks
=(4+27)/2 =31/2 , Hence E.
05 Jun 2021, 06:38
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Bunuel
Solution:
We simplify the given expression as follows:
- \(\frac{\sqrt[3]{64} + 3^3}{(16)^{\frac{1}{4}}}\)
= \(\frac{\sqrt[3]{4^3} + 3^3}{(2^4)^{\frac{1}{4}}}\)
= \(\frac{{4 + 3^3}}{2}\) (since \({\sqrt[n]{a^n}\) = a)
= \(\frac{{4 + 27}}{2}\)
= \(\frac{31}{2}\)
Hence, the correct answer is Option E.
