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1-6C4(2)^4/12C4=1-16/33=17/33

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A bag has 6 different pairs of socks. If 4 socks are randomly selected from the bag, what is the probability that at least 1 pair of socks is selected?

The number of ways to select 4 socks = = 12*11*10*9/4!
The number of ways that no pair of socks is selected = 12*10*8*6/4!

The probability that no pair of socks is selected = 12*10*8*6/12*11*10*9 = 16/33
The probability that at least 1 pair of socks is selected = 1 - 20/33 = 17/33

​​​​​​​IMO C
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