60 Boys take part in a local swimming competition. Half of the boys

Question

60 Boys take part in a local swimming competition. Half of the boys are allotted to Team 1 and half are allotted to Team 2. However , 80 percent of the boys prefer Team 1 and the remaining prefer Team 2 . What is the difference between the maximum and the minimum possible number of boys who will not be assigned to the team they prefer ?

A. 18
B. 24
C. 30
D. 42
E. 48

A. 18
B. 24
C. 30
D. 42
E. 48

PriyamRathor · Answer

Hello Experts 
 avigutman   Bunuel   JeffTargetTestPrep   chetan2u   GMATinsight

Please help to solve this problem .

Thanks

Pankaj10596 · Answer

Students in Team 1 - 30
Students in Team 2 -30
80% of students who prefer team 1 = 48
Rest students who prefer team 2 = 12
To calculate maximum number of students who will not get a team of their preferences, 
assume that all the students who prefer team 1 have been assigned to team 2 i.e. = 30 students
Now 12 students who want to join team 2 will be assigned to team 1.
Therefore, maximum students who will not get team of their preferences = 30+12 = 42 -----(1)

To minimize the number of students who will not get team they want, assume from all 48 students who prefer team 1 30 actually got into team 1. Now remaining 18 students will have to go to team 2 which they don't prefer.
12 students who prefer team 2 will get into team 2.
Hence, minimum number of students who will not get team of their preferences = 18 ----(2)

Answer would be (2) subtracted from (1) = 24 
Answer is (B)

wadhwakaran · Answer

PriyamRathor

Half of 60= 30
Team 1= 30, Team 2= 30
No of boys preferring Team 1= 48
No of boys preferring Team 2= 12

Maximum No of boys not getting desired team will be 42 
Let's assume all 30 boys in Team 2 were all those who wanted to get to Team 1. Additionally, there are 12 boys in Team 1 who wanted to join Team 2. Therefore total boys not getting the desired team is 42

Now the minimum no of boys not getting the desired team will be 18
Team 1 got all the 30 boys who wanted to join Team 1
Team 2 got all the 12 boys who wanted to join team 2
Now the remaining 18 boys in Team 2 will be those who wanted to join Team 1.

Therefore the difference will 42-18= 24

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chetan2u · Answer

Total : 60
 Preference : Team 1- 48( let these be called xs ) and Team 2- 12( let these be called ys)
 Distribution : Team 1- 30 and Team 2- 30

Maximum number of boys who do not get their preferred teams.  
Give 30 x to Team 2, so none in team 2 have their preference. Also. 12 y will automatically go to Team 1.
Thus, 42 do not get their preference.

Minimum number of boys who do not get their preferred teams.  
Give 30 x to Team 1, so all in team 1 have their preference. Also. 12 y will automatically go to Team 2 and get their preference.
Thus, 60-30-12 or 18 still do not get their preference.

Difference: 42-18=24

B

PriyamRathor

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60 Boys take part in a local swimming competition. Half of the boys

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