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RenB
Joined: 13 Jul 2022
Last visit: 02 Mar 2026
Posts: 389
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Location: India
Concentration: Finance, Nonprofit
Schools: Stanford '26 Wharton '26 (D) Booth '26 (D) Yale '26 (D) CBS '26 (A$$$) Darden '26 (WL) HBS '26 (D) Ross '26 (A$$$$) LBS '26 (D) Tuck '26 (A$$) Kellogg '26 (A)
GMAT Focus 1: 715 Q90 V84 DI82 
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WE:Corporate Finance (Consulting)
Schools: Stanford '26 Wharton '26 (D) Booth '26 (D) Yale '26 (D) CBS '26 (A$$$) Darden '26 (WL) HBS '26 (D) Ross '26 (A$$$$) LBS '26 (D) Tuck '26 (A$$) Kellogg '26 (A)
GMAT Focus 1: 715 Q90 V84 DI82
Posts: 389
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
61% (02:16) correct
39%
(02:26)
wrong
based on 1081
sessions
History
Date
Time
Result
Not Attempted Yet
Consider a 3 dimensional analog of a rectangular grid with dimensions 2 by 3 by 3. What is the number of paths from the front left-down vertex to the back-right up vertex such that each path consists of travelling only back, right or up?
A. 320
B. 480
C. 560
D. 600
E. 8!
OG Advanced quant- Tip section
(Bunuel or moderator- only the answer was given- kindly edit suitable options as required)
(Bunuel or moderator- only the answer was given- kindly edit suitable options as required)
01 May 2023, 04:23
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The image attached with the question is a bit misleading as it is a 2D image.
The 3D path can be visualized as shown below
Screenshot 2023-05-01 164850.jpg [ 11.39 KiB | Viewed 14304 times ]
To move from start to finish, one needs to go 3 units up, 3 units right, and 2 units back. However, the traversal can be in any order. Hence, the entire movement can be visualized as various arrangements of
R R R U U U B B
R ⇒ Right
U ⇒ Up
B ⇒ Back
The number of possible ways =\( \frac{8!}{3! * 3! * 2!}\) = 560
Option C
The 3D path can be visualized as shown below
Attachment:
Screenshot 2023-05-01 164850.jpg [ 11.39 KiB | Viewed 14304 times ]
To move from start to finish, one needs to go 3 units up, 3 units right, and 2 units back. However, the traversal can be in any order. Hence, the entire movement can be visualized as various arrangements of
R R R U U U B B
R ⇒ Right
U ⇒ Up
B ⇒ Back
The number of possible ways =\( \frac{8!}{3! * 3! * 2!}\) = 560
Option C
General Discussion
27 May 2023, 00:09
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Hello Bunuel,
I really need your help with this question. I know how to solve the path-based questions but I was not able to make an image by reading this question. I thought that 2 by 3 by 3 are lengths. I never imagine an image with blocks as explained by gmatophobia. What did I miss in this question? how should I have analyzed this question?
Also, The Answer will be:
\(\frac{8!}{3!*3!*2!}\)
why do we divide the 8! with 3!*3!*2!. In combination, we divide like this for repetition, is the same logic working here? if yes, can you explain?
Thank you in advance
I really need your help with this question. I know how to solve the path-based questions but I was not able to make an image by reading this question. I thought that 2 by 3 by 3 are lengths. I never imagine an image with blocks as explained by gmatophobia. What did I miss in this question? how should I have analyzed this question?
Also, The Answer will be:
\(\frac{8!}{3!*3!*2!}\)
why do we divide the 8! with 3!*3!*2!. In combination, we divide like this for repetition, is the same logic working here? if yes, can you explain?
Thank you in advance
