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SlowGuy
I've been stuck at this question for quite sometime. I see the answer. I'm wondering if someone can explain what the answer should be. (and why?)

If a, b, c, and d are distinct even integers and a is prime, is the four digit number abcd divisible by 8 ?
(1) The two digit number ba is a multiple of 21, and 40 is a factor of the two digit number dc.
(2) 10 is a divisor of the two digit number bc, and the product of a and d is a perfect square.

(A)       Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
(B)       Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
(C)       BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
(D)       EACH statement ALONE is sufficient.
(E)       Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data are needed.

Princeton Review (2012-05-22). 1,037 Practice Questions for the New GMAT, 2nd Edition:
Lets derive few pointers from this questions.

Firstly, a=2 becasue 2 is only even prime integer.
Secondly, we should concentrate on the values for b, c, d becasue if "bcd" is divisible by 8 than the four digit number abcd is divisible by 8.

My answer is E because i'm not able to find out from both the option that whether "bcd" is divisible by 8 or not.

Any takers?
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SlowGuy
I've been stuck at this question for quite sometime. I see the answer. I'm wondering if someone can explain what the answer should be. (and why?)

If a, b, c, and d are distinct even integers and a is prime, is the four digit number abcd divisible by 8 ?
(1) The two digit number ba is a multiple of 21, and 40 is a factor of the two digit number dc.
(2) 10 is a divisor of the two digit number bc, and the product of a and d is a perfect square.

(A)       Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
(B)       Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
(C)       BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
(D)       EACH statement ALONE is sufficient.
(E)       Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data are needed.

Princeton Review (2012-05-22). 1,037 Practice Questions for the New GMAT, 2nd Edition:
Lets derive few pointers from this questions.

Firstly, a=2 becasue 2 is only even prime integer.
Secondly, we should concentrate on the values for b, c, d becasue if b+c+d is divisible by 8 than the four digit number abcd is divisible by 8.

My answer is E because i'm not able to find out from both the option that whether b+c+d is divisible by 8 or not.

Any takers?

The divisibility rule for 8 says that the three digit number formed by the last digits must be divisible by 8, and not the sum of the last three digits.
So, ABC as a three digit number should be divisible by 8 and not the sum A + B + C. See 206 as an example.
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SlowGuy
I've been stuck at this question for quite sometime. I see the answer. I'm wondering if someone can explain what the answer should be. (and why?)

If a, b, c, and d are distinct even integers and a is prime, is the four digit number abcd divisible by 8 ?
(1) The two digit number ba is a multiple of 21, and 40 is a factor of the two digit number dc.
(2) 10 is a divisor of the two digit number bc, and the product of a and d is a perfect square.

(A)       Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
(B)       Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
(C)       BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
(D)       EACH statement ALONE is sufficient.
(E)       Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data are needed.

Princeton Review (2012-05-22). 1,037 Practice Questions for the New GMAT, 2nd Edition:

Necessarily \(a=2\) being the only even prime number.

(1) \(ba\) must be an even multiple of \(21,\) and since \(a=2,\) necessarily \(ba = 42,\) so \(b=4.\)
\(dc\) must be a multiple of \(40\); the only possibility is \(dc=80\) (\(dc\) cannot be \(40,\) as \(d\) must be different
from \(b=4\)). So \(d=8\) and \(c=0.\)
In conclusion, \(abcd=2408\).
Sufficient.
In fact, doesn't matter if this number is divisible by \(8,\) there is just one four digit number which fulfills the given conditions. In particular, \(2408\) is divisible by \(8.\)

(2) \(bc\) is a multiple of \(10,\) therefore \(c=0.\)
The product \(2\cdot{d}\) must be a perfect square, and since \(a=2\) and \(d\) must be different from \(a\) and \(c,\) the only possibility is \(d=8.\)
The four digit number is \(2b08\), and \(b\) can be either \(4\) or \(6.\)
Both \(2408\) and \(2608\) are divisible by \(8.\)
Sufficient.

Answer D
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SlowGuy
I've been stuck at this question for quite sometime. I see the answer. I'm wondering if someone can explain what the answer should be. (and why?)

If a, b, c, and d are distinct even integers and a is prime, is the four digit number abcd divisible by 8 ?
(1) The two digit number ba is a multiple of 21, and 40 is a factor of the two digit number dc.
(2) 10 is a divisor of the two digit number bc, and the product of a and d is a perfect square.

(A)       Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
(B)       Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
(C)       BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
(D)       EACH statement ALONE is sufficient.
(E)       Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data are needed.

Princeton Review (2012-05-22). 1,037 Practice Questions for the New GMAT, 2nd Edition:

Merging similar topics. Please refer tot he solutions above.

Also, please read carefully and follow: rules-for-posting-please-read-this-before-posting-133935.html
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Sorry about that. As you can tell, I am a new poster here.

Also, thanks a lot for meging the topics.


Bunuel

Merging similar topics. Please refer tot he solutions above.

Also, please read carefully and follow:
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IanStewart
enigma123
Question is:

From Statement 2, we know that

10 is a divisor of the two digit number bc

in which case it must be that c=0, since multiples of 10 end in 0.

and the product of ad is a perfect square.

Further, the product ad, which is equal to 2d, is a perfect square. Since d can only be 4, 6 or 8, (we've used 0 already), we can see that d must be 8. So we know that our number is 2b08, where b is either 4 or 6, and since 408 and 608 are each divisible by 8, we have sufficient information.

Now, there's either a typo in the original post or in the book, because the statements contradict each other. In Statement 1, perhaps it says 'dc' instead of 'cd' in the original source?

Shouldn't b= 2 or b=8?
how is 2*4 or 2*6 a perfect square?
Then ofcourse, b=2 is ruled out due to redundancy.

Please correct me, if I'm wrong.
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question stem says 40 is factor of cd and not dc

EvaJager
SlowGuy
I've been stuck at this question for quite sometime. I see the answer. I'm wondering if someone can explain what the answer should be. (and why?)

If a, b, c, and d are distinct even integers and a is prime, is the four digit number abcd divisible by 8 ?
(1) The two digit number ba is a multiple of 21, and 40 is a factor of the two digit number dc.
(2) 10 is a divisor of the two digit number bc, and the product of a and d is a perfect square.

(A)       Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
(B)       Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
(C)       BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
(D)       EACH statement ALONE is sufficient.
(E)       Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data are needed.

Princeton Review (2012-05-22). 1,037 Practice Questions for the New GMAT, 2nd Edition:

Necessarily \(a=2\) being the only even prime number.

(1) \(ba\) must be an even multiple of \(21,\) and since \(a=2,\) necessarily \(ba = 42,\) so \(b=4.\)
\(dc\) must be a multiple of \(40\); the only possibility is \(dc=80\) (\(dc\) cannot be \(40,\) as \(d\) must be different
from \(b=4\)). So \(d=8\) and \(c=0.\)
In conclusion, \(abcd=2408\).
Sufficient.
In fact, doesn't matter if this number is divisible by \(8,\) there is just one four digit number which fulfills the given conditions. In particular, \(2408\) is divisible by \(8.\)

(2) \(bc\) is a multiple of \(10,\) therefore \(c=0.\)
The product \(2\cdot{d}\) must be a perfect square, and since \(a=2\) and \(d\) must be different from \(a\) and \(c,\) the only possibility is \(d=8.\)
The four digit number is \(2b08\), and \(b\) can be either \(4\) or \(6.\)
Both \(2408\) and \(2608\) are divisible by \(8.\)
Sufficient.

Answer D
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