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07 Mar 2016, 03:30
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
86% (01:23) correct
14%
(01:29)
wrong
based on 84
sessions
History
Date
Time
Result
Not Attempted Yet
ENGRTOMBA2018
Joined: 20 Mar 2014
Last visit: 01 Dec 2021
Posts: 2,319
Own Kudos:
Given Kudos: 816
Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44
GPA: 3.7
WE:Engineering (Aerospace and Defense)
Products:
07 Mar 2016, 05:03
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Bunuel
p \(\neq\) 0 , is r<0?
Per statement 1, pr = 15, pr = positive ---> either both p,r >0 or both p,r < 0. Not sufficient.
Per statement 2, p+r=8, not sufficient as p=20, r =-12 or p=2, r = 6 give you 2 different answers for nature of r.
Combining, we get pr=15 and p+r=8 ---> p and r must be of the same sign ---> p and r can NOT both be negative as p+r in this case will become a negative quantity. Thus, the only acceptable case here is that p and r are both >0 . Hence sufficient.
C is thus the correct answer.
Bunuel , is it necessary to mention p \(\neq\) 0 ? Statement 1 mentions that p*r = a non zero value. Thus, both p and r must be non-zero.
07 Mar 2016, 05:23
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Bunuel
Question: Is r < 0 ?
Statement 1: pr=15
@p=3, r = 5 i.e. Greater than zero
@p=-3, r = -5 i.e. Less than zero
NOT SUFFICIENT
Statement 2: p + r = 8
@p=3, r = 5 i.e. Greater than zero
@p=10, r = -2 i.e. Less than zero
NOT SUFFICIENT
Combining the two statements
We know from first statement that sign of both p and r must be identical as their product is positive
In addition to the information from statement 1 we infer that
Statement 2 tells us that pand r both must be positive as sum of two negative numbers can't be 8
Hence after combining we get
that each of p and r must be POSITIVE
SUFFICIENT
Answer: option C
