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AbdurRakib
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A group of students, each of whom has prepared a presentation, is 05 Jun 2016, 14:32
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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57% (01:17) correct 43% (01:16) wrong based on 1371 sessions

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A group of students, each of whom has prepared a presentation, is asked to choose who will give presentations during the next class meeting and in what order they will be given. How many different ways are there to select and arrange the order of presentations?

(1) Five students must be chosen.

(2) All but three students must give presentations at the next class meeting.
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C
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A group of students, each of whom has prepared a presentation, is 06 Jun 2016, 11:43
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AbdurRakib
A group of students, each of whom has prepared a presentation, is asked to choose who will give presentations during the next class meeting and in what order they will be given. How many different ways are there to select and arrange the order of presentations?

(1) Five students must be chosen.

(2) All but three students must give presentations at the next class meeting.
Show more
Dear AbdurRakib,
I'm happy to respond. :-) This is a good question.

Statement #1: Five students must be chosen
Here, we don't know the pool. If there are only five students total, then there is only one group of individuals, and it is simply a matter of arranging them. If there are 100 students, then there would be a mindbogglingly large number of combinations of the five people that could be picked (you know have to know how to calculate this, but it's actually over seventy-five million!!) The number depends in part on the size of the pool. This statement, alone and by itself, is insufficient.

Now, we have to be very careful to blot the first statement from our minds and consider statement #2 in its pristine solitude.

Statement #2: All but three students must give presentations at the next class meeting.
Now, we know the number of "not chosens," but we have no idea how many are chosen. It could be that there are four students total, and one gives the presentation in the next class: this would result in simply four ways of choosing. Or there could be six students, and three give it next class: for this, even with out a calculation, we can see that there would be more than four ways of choosing. Without knowing definitely the number chosen, we cannot answer the prompt question. This statement, alone and by itself, is insufficient.

Now, consider the two statement together.
Now, five are chosen for next class, and 3 remain unchosen, so the total number of students with presentations is 8. How many combinations of 5 students can we pick from the 8? That's 8C5. Once, we have those five, we can put them in 5! orders. Thus, the total number of ways is
N = (8C5)(5!)
We don't need to calculate. It's enough to know that we could. Together, both statements are sufficient.
OA = (C)

For those curious about the calculation:
8C5 = 56
5! = 120

N = (8C5)(5!) = (56)(120) = 56(100 + 20) = 5600 + 1120 = 6720

Mike :-)
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A group of students, each of whom has prepared a presentation, is 29 Jan 2019, 07:53
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Hi chetan2u, Bunuel, VeritasKarishma, amanvermagmat, gmatbusters


I am not sure why answer is C as statement 2 states "3 must be chosen" but solution provided contrast with it

mikemcgarry

"Statement #2: All but three students must give presentations at the next class meeting.
Now, we know the number of "not chosens," but we have no idea how many are chosen"
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Could you please review and advise if I am missing something.
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A group of students, each of whom has prepared a presentation, is 29 Jan 2019, 08:10
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Gmatprep550
Hi chetan2u, Bunuel, VeritasKarishma, amanvermagmat, gmatbusters


I am not sure why answer is C as statement 2 states "3 must be chosen" but solution provided contrast with it

mikemcgarry

"Statement #2: All but three students must give presentations at the next class meeting.
Now, we know the number of "not chosens," but we have no idea how many are chosen"


Could you please review and advise if I am missing something.
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Hi,
Happy to help here :)
Pls reveiw the st.2 again, it says that "All but three students must give presentations at the next class meeting"- that means everyone other than 3 has to give the presentation, that simply means that 3 are not chosen
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A group of students, each of whom has prepared a presentation, is 29 Jan 2019, 08:13
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" ALL BUT " means except,
Statement 2 says: All but 3 means all students except 3 must give presentations. here total no of students are not known, and hence the number of students who gave presentation is not known.



Gmatprep550
Hi chetan2u, Bunuel, VeritasKarishma, amanvermagmat, gmatbusters


I am not sure why answer is C as statement 2 states "3 must be chosen" but solution provided contrast with it

mikemcgarry

"Statement #2: All but three students must give presentations at the next class meeting.
Now, we know the number of "not chosens," but we have no idea how many are chosen"


Could you please review and advise if I am missing something.
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A group of students, each of whom has prepared a presentation, is 06 Apr 2020, 08:36
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AbdurRakib
A group of students, each of whom has prepared a presentation, is asked to choose who will give presentations during the next class meeting and in what order they will be given. How many different ways are there to select and arrange the order of presentations?

(1) Five students must be chosen.

(2) All but three students must give presentations at the next class meeting.
Dear AbdurRakib,
I'm happy to respond. :-) This is a good question.

Statement #1: Five students must be chosen
Here, we don't know the pool. If there are only five students total, then there is only one group of individuals, and it is simply a matter of arranging them. If there are 100 students, then there would be a mindbogglingly large number of combinations of the five people that could be picked (you know have to know how to calculate this, but it's actually over seventy-five million!!) The number depends in part on the size of the pool. This statement, alone and by itself, is insufficient.

Now, we have to be very careful to blot the first statement from our minds and consider statement #2 in its pristine solitude.

Statement #2: All but three students must give presentations at the next class meeting.
Now, we know the number of "not chosens," but we have no idea how many are chosen. It could be that there are four students total, and one gives the presentation in the next class: this would result in simply four ways of choosing. Or there could be six students, and three give it next class: for this, even with out a calculation, we can see that there would be more than four ways of choosing. Without knowing definitely the number chosen, we cannot answer the prompt question. This statement, alone and by itself, is insufficient.

Now, consider the two statement together.
Now, five are chosen for next class, and 3 remain unchosen, so the total number of students with presentations is 8. How many combinations of 5 students can we pick from the 8? That's 8C5. Once, we have those five, we can put them in 5! orders. Thus, the total number of ways is
N = (8C5)(5!)
We don't need to calculate. It's enough to know that we could. Together, both statements are sufficient.
OA = (C)

For those curious about the calculation:
8C5 = 56
5! = 120

N = (8C5)(5!) = (56)(120) = 56(100 + 20) = 5600 + 1120 = 6720

Mike :-)
Show more

I am wondering why I cannot solve it like that: 8*7*6*5*4
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A group of students, each of whom has prepared a presentation, is 06 Apr 2020, 09:31
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yes u r right, we can find the different ways by using: 8*7*6*5*4

but to know that total is 8 students and that we need to select 5 : both statements are required, and hence answer is C.

How to answer Data Sufficiency Questions:



A) Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked.
B) Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked.
C) BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked.
D) EACH statement ALONE is sufficient to answer the question asked.
E) Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data specific to the problem are needed.



marikkka
mikemcgarry
AbdurRakib
A group of students, each of whom has prepared a presentation, is asked to choose who will give presentations during the next class meeting and in what order they will be given. How many different ways are there to select and arrange the order of presentations?

(1) Five students must be chosen.

(2) All but three students must give presentations at the next class meeting.
Dear AbdurRakib,
I'm happy to respond. :-) This is a good question.

Statement #1: Five students must be chosen
Here, we don't know the pool. If there are only five students total, then there is only one group of individuals, and it is simply a matter of arranging them. If there are 100 students, then there would be a mindbogglingly large number of combinations of the five people that could be picked (you know have to know how to calculate this, but it's actually over seventy-five million!!) The number depends in part on the size of the pool. This statement, alone and by itself, is insufficient.

Now, we have to be very careful to blot the first statement from our minds and consider statement #2 in its pristine solitude.

Statement #2: All but three students must give presentations at the next class meeting.
Now, we know the number of "not chosens," but we have no idea how many are chosen. It could be that there are four students total, and one gives the presentation in the next class: this would result in simply four ways of choosing. Or there could be six students, and three give it next class: for this, even with out a calculation, we can see that there would be more than four ways of choosing. Without knowing definitely the number chosen, we cannot answer the prompt question. This statement, alone and by itself, is insufficient.

Now, consider the two statement together.
Now, five are chosen for next class, and 3 remain unchosen, so the total number of students with presentations is 8. How many combinations of 5 students can we pick from the 8? That's 8C5. Once, we have those five, we can put them in 5! orders. Thus, the total number of ways is
N = (8C5)(5!)
We don't need to calculate. It's enough to know that we could. Together, both statements are sufficient.
OA = (C)

For those curious about the calculation:
8C5 = 56
5! = 120

N = (8C5)(5!) = (56)(120) = 56(100 + 20) = 5600 + 1120 = 6720

Mike :-)

I am wondering why I cannot solve it like that: 8*7*6*5*4
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A group of students, each of whom has prepared a presentation, is 15 Sep 2023, 10:23
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AbdurRakib
A group of students, each of whom has prepared a presentation, is asked to choose who will give presentations during the next class meeting and in what order they will be given. How many different ways are there to select and arrange the order of presentations?

(1) Five students must be chosen.

(2) All but three students must give presentations at the next class meeting.
Show more
i think it should be E as we do not know the total pool.
why didnt we assume that 5 are selected for the meeting in the next meeting? it can be easily inferred rght. and if not then inferred then for calculations of C why are we not inferring 5 are chosen for the meeting in the next particular class?
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A group of students, each of whom has prepared a presentation, is 15 Oct 2025, 23:45
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