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Bunuel
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Bunuel
Is y – z < x – z?

(1) y lies between x and z.
(2) z < x < 0

Statements 1 and 2 combined
Statement 1 tells us that EITHER x < y < z OR z < y < x
Statement 2 tells us that z < x, which RULES OUT the possibility that x < y < z
So, it MUST be the case that x < y < z, which means x < y
So, the answer to the REPHRASED target question is "NO. It is definitely NOT the case that y < x"
Since we can answer the REPHRASED target question with certainty, the combined statements are SUFFICIENT

Answer: C

Dear Brent,
While you RULES OUT the possibility that x < y < z, you then used the same ruled out possibility to reach the conclusion. You should have taken the other possibility that x < y < z and hence y<x . So, the answer you the target question should be YES.

Thanks
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Dear Brent,
While you RULES OUT the possibility that x < y < z, you then used the same ruled out possibility to reach the conclusion. You should have taken the other possibility that x < y < z and hence y<x . So, the answer you the target question should be YES.

Thanks

Good catch!
I've edited that portion.

Cheers and thanks,
Brent
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Bunuel
Is y – z < x – z?

(1) y lies between x and z.
(2) z < x < 0

If we add z to both sides of the equation, we can simplify the given question to read:

Is y < x ?

Statement One Alone:

y lies between x and z.

Although we know that y is between x and z, we still do not have enough information to solve the question. For instance, if z = -4, y = -2, and x = -1, then y < x; however if x = -4, y = -2, and z = -1, then y > x. Statement one alone is not sufficient to answer the question.

Statement Two Alone:

z < x < 0

Since we do not have any information regarding y, statement two alone is not sufficient to answer the question.

Statements One and Two Together:

Using the information from statements one and two, we can determine that z < y < x < 0, and thus, y is less than x.

Answer: C
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