Statement 1. Probability of drawing any number other than 3 = 50% which means tiles with number other than 3 constitute 50% of the total tiles. This means tiles with number '3' constitute 100-50 = 50% of the total tiles. So Probability in this case = 50%, which is NOT greater than 50%. The answer is NO.
Hence Sufficient.
Statement 2. If there are say 'n' 3's in the box and total number of tiles is say 'm', then probability of drawing two 3's:
P = n/m * (n-1)/(m-1)
This is given to be zero which means n(n-1) = 0.
n is thus either 0 or 1. So there are either 0 or 1 tiles in the box having number 3
We don't know the total number of tiles in the box. If there are only two total tiles in the box (m=2) then if n=0, probability would be 0 but if n=1, probability would be 50% (still NOT greater than 50%).
If there is a single tile in the box (m=1) then in any case we cannot draw two 3's from the box so probability would be 0 (still NOT greater than 50%).
If there are three tiles (m=3) then if n=0, probability would be 0 but if n=1, probability would be 1/3 or 33.33% (still NOT greater than 50%).
With increasing values of m, probability would keep on decreasing.. But it will always stay less than 50% as you can see.
The answer is NO. Statement is Sufficient to answer.
Hence D