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Bunuel
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mynamegoeson
Bunuel
In the diagram below, what is the measure of ∠BCD?


(1) AB is parallel to DE.
(2) ∠ABC = 550.


Attachment:
2017-07-25_1016.png

Hi Bunuel

is ∠ABC = 550 correct..i suppose it will be ∠ABC = 55 Degree

It's 55°. Edited. Thank you.
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Is it C??

Since both statements would be required to measure the angle BCD
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Let \(\angle BCD = x\)

Using statement 1:

From the new diagram attached, you can extend BC to intersect DE at a new point, say F.
The angle formed, i.e \(\angle CFD = \angle ABC = y\)

In triangle CFD, \(\angle CDF = 90 \angle FCD = 180 -x\)
180 - x + y + 90 = 180
x-y = 90

Hence 1 is insufficient.

Statement 2 gives us \(\angle ABC\) but we dont know if AB and DE are ||

Using 1 and 2, we can find \(\angle BCD = 180 - 35 = 145\)
Attachments

slice1.png
slice1.png [ 10.69 KiB | Viewed 3934 times ]

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