Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
03 Oct 2017, 00:05
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
50% (02:04) correct
50%
(02:05)
wrong
based on 377
sessions
History
Date
Time
Result
Not Attempted Yet
Is \(r^x<100\) ?
(1) \(r∗\sqrt[3]{x}>100\)
if x = 1/8
=> \(r∗\sqrt[3]{\frac{1}{8}}>100\)
=> \(r*\frac{1}{2} > 100\)
=> r > 200
\(r^x<100\)
=>\(300^{\frac{1}{8}}<100\) True
if x = 8
=> r > 50
\(r^x<100\)
=>\(51^{8}<100\) False
So here we don't have max and min of x and r, so we cannot calculate value of \(r^x<100\)
Insufficient
(2) x>1
Here we dont know value of r
Insufficient
1+2
\(r∗\sqrt[3]{x}>100\) and x>1
for x =8>1 => \(r∗\sqrt[3]{x}>100\)
=> \(r∗\sqrt[3]{8}>100\)
=> r >50
so \(r^x<100\)
=> \(51^8<100\) False
for x=100000000
\(r∗\sqrt[3]{x}>100\)
=> \(r∗\sqrt[3]{100000000}>100\)
=> r* 1000>100
=> r >1/10
so \(r^x<100\)
=> \(1^{1000000000}<100\) True
So here there is no max limit on x. Hence insufficient
Answer: E
(1) \(r∗\sqrt[3]{x}>100\)
if x = 1/8
=> \(r∗\sqrt[3]{\frac{1}{8}}>100\)
=> \(r*\frac{1}{2} > 100\)
=> r > 200
\(r^x<100\)
=>\(300^{\frac{1}{8}}<100\) True
if x = 8
=> r > 50
\(r^x<100\)
=>\(51^{8}<100\) False
So here we don't have max and min of x and r, so we cannot calculate value of \(r^x<100\)
Insufficient
(2) x>1
Here we dont know value of r
Insufficient
1+2
\(r∗\sqrt[3]{x}>100\) and x>1
for x =8>1 => \(r∗\sqrt[3]{x}>100\)
=> \(r∗\sqrt[3]{8}>100\)
=> r >50
so \(r^x<100\)
=> \(51^8<100\) False
for x=100000000
\(r∗\sqrt[3]{x}>100\)
=> \(r∗\sqrt[3]{100000000}>100\)
=> r* 1000>100
=> r >1/10
so \(r^x<100\)
=> \(1^{1000000000}<100\) True
So here there is no max limit on x. Hence insufficient
Answer: E
General Discussion
03 Oct 2017, 03:20
Kudos
Bookmarks
Ans : c
1. r * x^1/3 > 100
consider x= positive (eg x= 27 and r =50)
Putting the values 125>100
Substituting x and r values in the given equation , r^x>100
Consider x= negative (eg x= -1 and r = -101)
Putting the values 101>100
Substituting x and r values in the given equation ,
r^x<100
NOt sufficient .
1.x > 1.
Statement alone is not sufficient as r can be any value.
Combining the two and subsituting anyvalue of x>1 and r that satisfies equation 1 ,
r^x is not less than 100 anytime.
1. r * x^1/3 > 100
consider x= positive (eg x= 27 and r =50)
Putting the values 125>100
Substituting x and r values in the given equation , r^x>100
Consider x= negative (eg x= -1 and r = -101)
Putting the values 101>100
Substituting x and r values in the given equation ,
r^x<100
NOt sufficient .
1.x > 1.
Statement alone is not sufficient as r can be any value.
Combining the two and subsituting anyvalue of x>1 and r that satisfies equation 1 ,
r^x is not less than 100 anytime.
. Thanks for highlighting, will edit the solution 
