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GMATinsight:

Statement 2: Each of the four shaded regions between the square and the circle has an area equal to 9 – 9/4*π.
i.e. (1/4[(2r)2−πr2]=9−(9/4)π(1/4[(2r)2−πr2]=9−(9/4)π
i.e. r = 3
i.e. r is NOT greater than 4 hence

Hello, could you please explain statement 2:
LHS of i.e. (1/4[(2r)2−πr2]=9−(9/4)π

How did you arrive at it?
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archish3113
GMATinsight:

Statement 2: Each of the four shaded regions between the square and the circle has an area equal to 9 – 9/4*π.
i.e. (1/4[(2r)2−πr2]=9−(9/4)π(1/4[(2r)2−πr2]=9−(9/4)π
i.e. r = 3
i.e. r is NOT greater than 4 hence

Hello, could you please explain statement 2:
LHS of i.e. (1/4[(2r)2−πr2]=9−(9/4)π

How did you arrive at it?

archish3113

One shaded portion at one of the corners = (1/4)*(Area of Square - Area of Circle) = \((1/4)*[(2r)^2−πr^2]=9−(9/4)π\)

Side of the square = 2r i.e. area of square = \((2r)^2\)

I hope this helps!!!

P.S. The Circle is inscribed in square i.e. Circle is tightly packed and touching all sides of teh square
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GMATinsight : understood where I was going wrong, thanks ...
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