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21 Jan 2020, 04:38
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
88% (01:06) correct
12%
(01:09)
wrong
based on 146
sessions
History
Date
Time
Result
Not Attempted Yet
How long will it take for two pipes A and B to fill an empty cistern if they worked alternately for an hour each?
(1) Working alone, Pipe A can fill the cistern in 40 hours
(2) Pipe B is one third as efficient as Pipe A
(1) Working alone, Pipe A can fill the cistern in 40 hours
(2) Pipe B is one third as efficient as Pipe A
21 Jan 2020, 06:17
Kudos
Bookmarks
Bunuel
Question: Time taken to fill the cistern if they work alternately = ?
Statement 1: Working alone, Pipe A can fill the cistern in 40 hours
We do NOT know the rate of Pipe B hence
NOT SUFFICIENT
Statement 2: Pipe B is one third as efficient as Pipe A
B = A/3 but we need to calculate the time and we do NOT have any specifics of time taken by A and B hence
NOT SUFFICIENT
Combining the two statements
A fills in 40 hours i.e .Time of Pipe B = 3*30 = 120 hours
No we can find how much time will they take to fill the tank as we have the exact rates of pipes hence
SUFFICIENT
Answer: Option C
Archit3110
Major Poster
22 Jan 2020, 01:35
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Bookmarks
#1
Working alone, Pipe A can fill the cistern in 40 hours Ra ; 1/40
Rb not know insufficient
#2
Rb = 1/3 * Ra ;
insufficient as Ra not know
from 1 & 2
we have Ra & Rb with us
IMO C sufficient
in 1 hr Ra ; 1/40 filled left with 39/40 which shall be fillled by b ; 117 hrs
Working alone, Pipe A can fill the cistern in 40 hours Ra ; 1/40
Rb not know insufficient
#2
Rb = 1/3 * Ra ;
insufficient as Ra not know
from 1 & 2
we have Ra & Rb with us
IMO C sufficient
in 1 hr Ra ; 1/40 filled left with 39/40 which shall be fillled by b ; 117 hrs
Bunuel
