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IMO A.

We are asked what is the value of b.

Statement I:
We can write b(b-8) = -16 as b^2 - 8b + 16 = 0
This is the same as saying (b - 4)^2 = 0

Therefore, b = 4.

Statement I is SUFFICIENT.

We can eliminate options B, C and E.

Lets look at Statement II:
(b + 4)^2 = 64
This is the same as b^2 + 8b - 48 = 0.

From the above equation we get two values of b i.e. 12 and -4.

Therefore Statement II is INSUFFICIENT.

We can eliminate option D.

Answer: A

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1) b(b-8) = -16
=> b^2 -8b +16 = 0
=> (b - 4)^2 = 0
=> b = 4
Sufficient

2) (b + 4)^2 = 64
=> b + 4 = \(\sqrt{64}\)
=> b + 4 = +8 or -8
=> b = 4 or -12
Not Sufficient

Hence OA is (A)
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Statement 1:
\(b(b - 8) = -16\)
\(=> b^2 - 8b + 16 = 0\)
\(=> (b - 4)^2 = 0\)
\(=> b - 4 = 0\)
=> b = 4
Hence, sufficient alone.

Statement 2:
\((b + 4)^2 = 64\)
=> b + 4 = 8 or b + 4 = -8
=> b = 4 or b = -12
Hence, insufficient.

Thus, OA is (A).
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(1) b(b - 8) = -16

gives b^2 -8b +16 = 0
(b-4)(b-4) = 0
gives b =4 sufficent

(2) (b + 4)^2 = 64
(b+4) = +/- 8
b = 4 or -12 so not sufficient

hence A
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Kindly see the attachment.

TIME: 0:58
IMO A

Attachments

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1) b(b-8) = -16
this equation gives two identical solutions for b. SUFFICIENT

2) (b+4)^2 = 64
==> (b+4) = +/- 8
This equation gives two solutions for b, NOT SUFFICIENT

IMO A
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Quote:
What is the value of b?

(1) b(b - 8) = -16
(2) (b + 4)^2 = 64

Question: b = ?

Statement 1: b(b - 8) = -16

i.e. b = 4

SUFFICIENT

Statement 2: (b + 4)^2 = 64

i.e. b+4 = +8 or -8
i.e. b = +4 or -12

NOT SUFFICIENT

Answer: Option A
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Statement 1 is sufficient to answer the question but not statement 2.
From statement 1:
b=4
From statement 2;
b=4 or -8

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Value of b?

Statement 1
b(b-8)=-16
b^2 - 8b = -16
b^2 - 8b +16 = 0
b^2 -4b -4b +16=0
b(b-4) -4(b-4)=0
(b-4)(b-4)=0
b-4=0
b=4.
We have a value for b which is 4, Let's Hold on to A and move to 2nd Statement.

Statement 2
(b+4)^2=64
2 ways to go about(What I feel)
1st way
(b+4)^2=64
Cancel Square on both sides
(b+4)= Positive8
or
(b+4)= Negative8
As nothing is specified. Can't say Really

2nd way
Open the square
(b+4)^2=64
b^2+2(b)(4) + 16 = 64
b^2 +8b +16 - 64=0
b^2+8b-48=0
b^2 +12b-4b-48=0
b(b+12)-4(b+12)=0
(b+12)(b-4)=0
b can be -12 or b can be +4
Can't Say Really. Statement 2 Not sufficient.

As statement 1 is only Sufficient ans is Option A.
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What is the value of b?

(1) b(b - 8) = -16
(2) (b + 4)^2 = 64

The answer should be A

st1) b(b-8) = -16
b^2 - 8b + 16 = 0
=> (b-4)^2 = 0
=> b = 4 (SUFFICIENT)

st2) b+4 = 8 or b+4 = -8
So b = 4 or -12 (INSUFFICIENT)
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What is the value of b?

(1) b(b - 8) = -16
(2) (b + 4)^2 = 64

1) b^2 - 8b + 16 =0, or, (b -4)^2 = 0, b = 4. sufficient.

2) b^2 + 8b + 16 -64 = 0, or, b^2 +8b - 48 = 0, or, b^2 +12b -4b -48 =0, or,b(b+12) -4 (b +12) =0, or, (b+12) (b-4)=0. b can be either -12 or 4. not sufficient

A is the answer.
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IMO A

value of b?

(1) b(b - 8) = -16

b^2 -8b+16 = 0
b^2-4b-4b+16=0
(b-4)(b-4)=0
(b-4)^2=0
b=4 (equal roots)

Sufficient

(2) (b + 4)^2 = 64

(b + 4)^2 = 64
(b + 4) = ± 8
b= -4 ± 8
b= -12 0r b=4

Not Sufficient
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Quote:
What is the value of b?

(1) b(b - 8) = -16
(2) (b + 4)^2 = 64

(1) sufic

b^2-8b+16=0, (b-4)^2=0, b=4

(2) insufic

b^2+16+8b-64=0, b^2+8b-48=0
(b+12)(b-4)=0, b={-12,4}

Ans (A)
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What is the value of b?

(1) b(b - 8) = -16
(2) (b + 4)^2 = 64

1) b^2-8b+16 = 0
(b-4)(b-4) = 0
b=4
sufficient

2) b+4=8, b+4=-8
b=4, -12
insufficient

Ans A
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