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A+B+C=306
Median value is what we are looking for.

1)
A=102
B+C+102=306
B+C=204
Lets take the case of B=C
2B=204
B=C=102
So we have the set (102,102,102)
Notice that the above tells us that if there is a book that is over 102, some other book must cost less than 102 so that the sum=204 This implies that, no matter what value of B and C you have you will always have 102 as the middle value.
Ex:
B=1, C=203
B=101, C=103
and for any combination between them it holds

Sufficient

2)
B=20+C
A+2C+20=306
A+2C=286
If A=2, 2C=284, C=142, B=162 (median=142)
If A=10, 2C=276, C=138, B=158 (median=138)
So we cannot apply the same reasoning that was applied in A, as the value of B depends on C and it is not a fixed value.
INS

A
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