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07 Apr 2026, 19:00
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B
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Difficulty:
45%
(medium)
Question Stats:
67% (01:46) correct
33%
(01:50)
wrong
based on 55
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For a production run, the number of inspection hours required, h, is given by h = 14 + p/80, where p is the number of units produced in the run. If one production run was completed on each of two days, Monday and Tuesday, how many more inspection hours were required for the Tuesday production run than for the Monday production run?
(1) The ratio of the number of units produced on Tuesday to the number produced on Monday was 3:1.
(2) 560 more units were produced on Tuesday than on Monday.
(1) The ratio of the number of units produced on Tuesday to the number produced on Monday was 3:1.
(2) 560 more units were produced on Tuesday than on Monday.
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15 Apr 2026, 01:15
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GMAT Club Official Solution:
For a production run, the number of inspection hours required, h, is given by h = 14 + p/80, where p is the number of units produced in the run. If one production run was completed on each of two days, Monday and Tuesday, how many more inspection hours were required for the Tuesday production run than for the Monday production run?
Let M be the number of units produced on Monday and T be the number of units produced on Tuesday. Then the inspection hours were:
Monday: 14 + M/80
Tuesday: 14 + T/80
So the difference is:
(14 + T/80) - (14 + M/80) = (T - M)/80
Thus, the question really asks for (T - M)/80.
(1) The ratio of the number of units produced on Tuesday to the number produced on Monday was 3:1.
This gives T : M = 3 : 1, so T = 3M. Therefore,
(T - M)/80 = (3M - M)/80 = 2M/80 = M/40
Since M is unknown, the difference cannot be determined. Not sufficient.
(2) 560 more units were produced on Tuesday than on Monday.
This gives T - M = 560, so:
(T - M)/80 = 560/80 = 7
Sufficient.
Answer: B.
For a production run, the number of inspection hours required, h, is given by h = 14 + p/80, where p is the number of units produced in the run. If one production run was completed on each of two days, Monday and Tuesday, how many more inspection hours were required for the Tuesday production run than for the Monday production run?
Let M be the number of units produced on Monday and T be the number of units produced on Tuesday. Then the inspection hours were:
Monday: 14 + M/80
Tuesday: 14 + T/80
So the difference is:
(14 + T/80) - (14 + M/80) = (T - M)/80
Thus, the question really asks for (T - M)/80.
(1) The ratio of the number of units produced on Tuesday to the number produced on Monday was 3:1.
This gives T : M = 3 : 1, so T = 3M. Therefore,
(T - M)/80 = (3M - M)/80 = 2M/80 = M/40
Since M is unknown, the difference cannot be determined. Not sufficient.
(2) 560 more units were produced on Tuesday than on Monday.
This gives T - M = 560, so:
(T - M)/80 = 560/80 = 7
Sufficient.
Answer: B.
General Discussion
07 Apr 2026, 23:42
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Given: h = 14 + p/80
We want: difference in hours (Tuesday − Monday)
Let Monday = p1, Tuesday = p2
Difference in hours
=> (14 + p2/80) − (14 + p1/80)
=> (p2 − p1)/80
So the question reduces to: what is (p2 − p1)?
Statement 1:
=> ratio Tuesday : Monday = 3 : 1
Let Monday = 100, Tuesday = 300
Difference = 200 → hours = 200/80 = 2.5
Now try another value
Monday = 200, Tuesday = 600
Difference = 400 → hours = 400/80 = 5
Different answers → not sufficient
Statement 2:
=> Tuesday produced 560 more units
So p2 − p1 = 560
Hours difference = 560/80 = 7
Unique answer → sufficient
Final answer: B
We want: difference in hours (Tuesday − Monday)
Let Monday = p1, Tuesday = p2
Difference in hours
=> (14 + p2/80) − (14 + p1/80)
=> (p2 − p1)/80
So the question reduces to: what is (p2 − p1)?
Statement 1:
=> ratio Tuesday : Monday = 3 : 1
Let Monday = 100, Tuesday = 300
Difference = 200 → hours = 200/80 = 2.5
Now try another value
Monday = 200, Tuesday = 600
Difference = 400 → hours = 400/80 = 5
Different answers → not sufficient
Statement 2:
=> Tuesday produced 560 more units
So p2 − p1 = 560
Hours difference = 560/80 = 7
Unique answer → sufficient
Final answer: B
