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13 Mar 2018, 08:33
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Difficulty:
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Question Stats:
74% (01:27) correct
26%
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based on 119
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What is the value of x?
(1) \(\sqrt{x^4} = 9\)
(2) The average (arithmetic mean) of x^2, 6x, and 3 is -2
(1) \(\sqrt{x^4} = 9\)
(2) The average (arithmetic mean) of x^2, 6x, and 3 is -2
13 Mar 2018, 10:19
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1. rt x^4 = 9 => x= -3, +3 NS
2. x^2 + 6x + 3 = -6 => (x+3)=0 or -(x+3)=0 => x= -3, +3 NS
1. & 2. x= -3, +3 NS
Thus E
2. x^2 + 6x + 3 = -6 => (x+3)=0 or -(x+3)=0 => x= -3, +3 NS
1. & 2. x= -3, +3 NS
Thus E
13 Mar 2018, 10:48
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u1983
Hello
As per your second statement analysis:
whether x+3 = 0 or -(x+3) = 0 ; isnt x always going to be '-3' only? So isnt the second statement sufficient on its own?
