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What is the value of x?

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What is the value of x?  [#permalink]

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New post 13 Mar 2018, 08:33
00:00
A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

70% (01:18) correct 30% (01:26) wrong based on 54 sessions

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Re: What is the value of x?  [#permalink]

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New post 13 Mar 2018, 10:19
1. rt x^4 = 9 => x= -3, +3 NS
2. x^2 + 6x + 3 = -6 => (x+3)=0 or -(x+3)=0 => x= -3, +3 NS
1. & 2. x= -3, +3 NS

Thus E
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Re: What is the value of x?  [#permalink]

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New post 13 Mar 2018, 10:48
u1983 wrote:
1. rt x^4 = 9 => x= -3, +3 NS
2. x^2 + 6x + 3 = -6 => (x+3)=0 or -(x+3)=0 => x= -3, +3 NS
1. & 2. x= -3, +3 NS

Thus E


Hello

As per your second statement analysis:
whether x+3 = 0 or -(x+3) = 0 ; isnt x always going to be '-3' only? So isnt the second statement sufficient on its own?
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Re: What is the value of x?  [#permalink]

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New post 13 Mar 2018, 11:03
yes.... u r rt... missed that part ... in that case B
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What is the value of x?  [#permalink]

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New post 13 Mar 2018, 18:51
1) \(\sqrt{x^4}\) = 9
\(x^\frac{4}{2}\) = 9
\(x^2\) = 9
x= +3 or -3
insuff

(2) The average (arithmetic mean) of x^2, 6x, and 3 is -2

\(\frac{x^2+6x+3}{3}\)= -2
\(x^2+6x+3\) = -6
\(x^2+6x+9 = 0\)
(x+3) (x+3) = 0
x=-3
suff


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What is the value of x? &nbs [#permalink] 13 Mar 2018, 18:51
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