Bunuel
If k is an integer, is k even?
(1) k + 5 is not an even integer
(2) k/2 is an even integer
Kudos for a correct solution.Since k is an integer, it can take any value from -infinity to +infinity including 0.
We can obtain an odd number only when an ODD number is ADDED to an EVEN number. In all other cases, we always get an even number (i.e. Even + Even, Odd + Odd)
1) Using first condition, we know that k + 5 is an ODD integer.
Hence we're sure that k is an EVEN integer because 5 is odd.
Hence this alone can help us answer the question.
2) Using second condition, we know that k/2 is an even integer.
The basic rule to test Even/Odd numbers is that if any integer when divided by 2 given an even integer then that integer is even.
Since k/2 is an even integer so k is an even integer.
Hence this alone can help us answer the question.
Hence the answer is D.
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