Bunuel
If x and y are integers, and x ≠ 0, what is the value of x^y?
(1) |x| = 2
(2) 64^x*6^(2x + y) = 48^(2x)
MANHATTAN GMAT OFFICIAL SOLUTION:Since x ≠ 0, we know that xy does not equal 0y or 0. To determine the exact non-zero value of xy, we need either the values of both x and y, or if y is even, the values of |x| and y (an even exponent “hides the sign” of the base, so we wouldn't need to know x's sign).
(1) INSUFFICIENT: This statement tells us that x is equal to 2 or –2. However, we know nothing about y and cannot determine the value of xy.
(2) SUFFICIENT: Simplify using exponent rules, noting the common factors of 6 and 8 on each side of the equation:
\(64^x*6^{2x + y} = 48^{2x}\)
\((8^2)^x *6^{2x + y} = (6*8)^{2x}\)
\(8^{2x}* (6^{2x}*6^y) = 6^{2x}*8^{2x}\)
\(6^y = 1\)
\(y = 0\)
Since y = 0 and x ≠ 0 (as stated in the question stem), this information is sufficient to conclude that \(x^y = x^0 = 1\).
The correct answer is B.