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Simplifying:

\(\frac{3}{4} + \frac{3}{4} + \frac{3}{4} = \frac{9}{4} = \frac{225}{100} = 2.25\)

Answer = C
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Just wondering how you guys assumed the square root of the numbers are only positive? Isn't it possible to have a combination of negative roots as well? Thanks!
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gmatchess
Just wondering how you guys assumed the square root of the numbers are only positive? Isn't it possible to have a combination of negative roots as well? Thanks!


As far as GMAT is concerned

Root of a "Number" is always +ve i.e. \sqrt{9} = 3

However, \sqrt{X^2} = Mod X = +/- X
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gmatchess
Just wondering how you guys assumed the square root of the numbers are only positive? Isn't it possible to have a combination of negative roots as well? Thanks!

When the GMAT provides the square root sign for an even root, such as a square root, fourth root, etc. then the only accepted answer is the positive root.

That is:
\(\sqrt{9} = 3\), NOT +3 or -3;
\(\sqrt[4]{16} = 2\), NOT +2 or -2;

Notice that in contrast, the equation \(x^2 = 9\) has TWO solutions, +3 and -3. Because \(x^2 = 9\) means that \(x =-\sqrt{9}=-3\) or \(x=\sqrt{9}=3\).

Hope it's clear.
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avohden


A. 0.75
B 1.5
C. 2.25
D. 3
E. 3.75

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