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sasyaharry
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30 Oct 2017, 17:15
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
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74% (01:17) correct
26%
(01:36)
wrong
based on 23
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If \(N = 2^2 * 3^3 * 5^5\), find the total number of odd and even factors of \(N\).
A) 24, 96
B) 15, 30
C) 24, 48
D) 15, 96
E) 15, 48
A) 24, 96
B) 15, 30
C) 24, 48
D) 15, 96
E) 15, 48
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sobby
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30 Oct 2017, 19:28
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sasyaharry
even factor = 2 * 4 * 6 = 48 (we need to exclude 2^0 here)
Odd factor = 6 * 4 = 24 (Exclude all 2's factor here )
30 Oct 2017, 19:46
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total no. of factors for the above set will be = 3 * 4 * 6 = 72
and (total odd factors ) + ( total even factors ) = 72
only option C has the sum of 72, hence answer C.
sobby can please explain your approach that you used to determine odd and even factors independently.
and (total odd factors ) + ( total even factors ) = 72
only option C has the sum of 72, hence answer C.
sobby can please explain your approach that you used to determine odd and even factors independently.
