Let's break down the information given in the problem:
90 students represent x percent of the boys at Jones Elementary School.
The boys at Jones Elementary make up 40% of the total school population of x students.
Let's use algebra to solve for x.
Let's assume that B is the total number of boys at Jones Elementary School, and T is the total school population.
From the first statement, 90 students represent x percent of the boys at Jones Elementary School. So we can write this as:
90 = (x/100) * B
From the second statement, the boys at Jones Elementary make up 40% of the total school population of x students. So we can write this as:
B = (40/100) * x
Now, we have two equations:
90 = (x/100) * B
B = (40/100) * x
Since we have two equations and two unknowns (x and B), we can solve for x.
First, let's solve for B in terms of x from the second equation:
B = (40/100) * x
B = (2/5) * x
Now, we can substitute this value of B into the first equation:
90 = (x/100) * B
90 = (x/100) * ((2/5) * x)
Now, simplify the equation:
90 = (2x^2/500)
Next, let's solve for x:
90 * 500 = 2x^2
45000 = 2x^2
x^2 = 45000 / 2
x^2 = 22500
Now, take the square root of both sides to find the positive value of x:
x = √22500
x ≈ 150.0
So, the total school population (x) is 150 students.
Hence B