Last visit was: 22 Apr 2026, 15:14 It is currently 22 Apr 2026, 15:14
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
parkhydel
Joined: 03 Jun 2019
Last visit: 04 Feb 2026
Posts: 273
Own Kudos:
22,911
 [40]
Given Kudos: 70
Posts: 273
Kudos: 22,911
 [40]
2
Kudos
Add Kudos
38
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Sajjad1994
User avatar
GRE Forum Moderator
Joined: 02 Nov 2016
Last visit: 22 Apr 2026
Posts: 16,839
Own Kudos:
51,892
 [4]
Given Kudos: 6,334
GPA: 3.62
Products:
Posts: 16,839
Kudos: 51,892
 [4]
2
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
General Discussion
User avatar
Sumi1010
Joined: 21 Aug 2018
Last visit: 19 Jan 2025
Posts: 295
Own Kudos:
Given Kudos: 20
Location: India
Posts: 295
Kudos: 698
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
suchithra
Joined: 31 Oct 2015
Last visit: 14 Oct 2022
Posts: 89
Own Kudos:
Given Kudos: 179
Posts: 89
Kudos: 119
Kudos
Add Kudos
Bookmarks
Bookmark this Post
If B=2 , then we have Area = \frac{1}{2}*2*2 = 2 km2 and C=\(\sqrt{4+4}\)=\(2\sqrt{2}\)= 2.8

Therefore C=2.8 and A=2 is the answer.
avatar
TarunKumar1234
Joined: 14 Jul 2020
Last visit: 28 Feb 2024
Posts: 1,102
Own Kudos:
Given Kudos: 351
Location: India
Posts: 1,102
Kudos: 1,357
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Given, In Right angled triangle, one side = 2, another perpendicular side = b and hypotenuse (longest side) = c

So, Area = A = 1/2 *base *height = 1/2 * 2*b = b.....(equation)

Condition 1: Say A = 2 = b (from above equation), C = Sqrt (b^2 + 2^2)= Sqrt (2^2 + 2^2)= 2*sqrt(2)= 2.8
So, A = 2 and C= 2.8 (Ans.)

Condition 2: A= 2.8 =b (from above equation), C = Sqrt (b^2 + 2^2) = Sqrt(2.8^2 + 4) = 3.44 (we don't have such value)

Condition 3: A= 4 =b (from above equation), C = Sqrt (b^2 + 2^2) = Sqrt(4^2 + 4) = 4.47 (we don't have such value)

Condition 4: A= 5.7 =b (from above equation), C = Sqrt (b^2 + 2^2) = Sqrt(5.7^2 + 4) = 6.04 (we don't have such value)

Condition 5: A= 8 =b (from above equation), C = Sqrt (b^2 + 2^2) = Sqrt(8^2 + 4) = 8.2 (we don't have such value)
User avatar
jhavyom
Joined: 02 Sep 2019
Last visit: 17 Dec 2022
Posts: 173
Own Kudos:
Given Kudos: 28
Location: India
Schools: ISB'22
Schools: ISB'22
Posts: 173
Kudos: 268
Kudos
Add Kudos
Bookmarks
Bookmark this Post
A farmer has a plot of land whose boundary is formed by two perpendicular roads and forms a right triangle. The length of the boundary along one of the roads is 2 kilometers (km), the length of the boundary along the other road is b km, the length of the longest side of the boundary is c km, and the area is A km2.

The hypotenuse of the triangle = c
The remaining two sides of the triangle = 2 and b
Area = 1/2 * 2 * b
= b

For b = 2
Area will be 2
and hypotenuse (c) will be
\(c = \sqrt{2^2 + b^2}\)
\(c = 2\sqrt{2}\)
= 2.82

Answers are B and A respecively.
User avatar
rocky620
User avatar
Retired Moderator
Joined: 10 Nov 2018
Last visit: 11 May 2023
Posts: 482
Own Kudos:
Given Kudos: 229
Location: India
Concentration: General Management, Strategy
GMAT 1: 590 Q49 V22
WE:Other (Retail: E-commerce)
GMAT 1: 590 Q49 V22
Posts: 482
Kudos: 625
Kudos
Add Kudos
Bookmarks
Bookmark this Post
As per the information:

c = Hypotenuse, Let b & 2 be base and height of the right angles triangle

Since Area, a= \(\frac{1}{2}\)*Base*Height = \(\frac{1}{2}\)*b*2 => A=b.......Eq1

\(c^2\) = \(b^2\) + \(h^2\)
\(c^2\) = \(b^2\) + 4
Replacing b with a From Eq1

\(c^2\) = \(a^2\) + \(4\)
\(c^2\) - \(a^2\) = \(4\)

We need a pair of values whose difference is 4

\(2^2\) = 4
\(2.8^2\) = 7.84
\(4^2\) = 16
\(5.7^2\) = 32.49
\(8^2\) = 64
Only the difference of \(2.8^2\) and \(2^2\) is closer to 4 (3.84)

SO, C=2.8 ; A=2
avatar
Deepakjhamb
Joined: 29 Mar 2020
Last visit: 15 Sep 2022
Posts: 216
Own Kudos:
Given Kudos: 14
Location: India
Concentration: General Management, Leadership
GPA: 3.96
WE:Business Development (Telecommunications)
Posts: 216
Kudos: 137
Kudos
Add Kudos
Bookmarks
Bookmark this Post
answer 1 )

c^2 = b^2 + 2^2 and A = 1/2 * b*2 , so A = b

so C = Underroot (b^2+ 4 ) and A=b

now we need to take various values of A and see if some value matches with c accordingly

we start the table :

we get A = 2 C = 2.82
A=2.8 C=3.44
A=4 C=4.47
A=5.7 C=6.04
A=8 C = 8.24


SO thus we see that only A=2 and C=2.8 In the table fit very closely with the values we get from equation

so answer is A=2 and C=2.8
User avatar
jabhatta2
Joined: 15 Dec 2016
Last visit: 21 Apr 2023
Posts: 1,251
Own Kudos:
Given Kudos: 188
Posts: 1,251
Kudos: 328
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hey avigutman - was wondering - could you solve this IR question W/O any calculator ?

I dont think it is possible w/o the calculator, given the closeness of the numbers.

using approximation tecniques -- i thougth these pairs were very close

(i) a = 2.8 and c = 4

---------

(ii)
a = 5.7 and c = 5.7 (both a and c could be 5.7)
IF a = 5.7, then \(a^2\) should be = approx 30
c = \(\sqrt{a^2 + 4}\) = \(\sqrt{Approx. 34}\)
c = \(\sqrt{Approx. 34}\), which is close to 6 ish or 5.9 ish
5..9 ish -- is close to -- 5.7 as well.
User avatar
avigutman
Joined: 17 Jul 2019
Last visit: 30 Sep 2025
Posts: 1,285
Own Kudos:
1,906
 [2]
Given Kudos: 66
Location: Canada
GMAT 1: 780 Q51 V45
GMAT 2: 780 Q50 V47
GMAT 3: 770 Q50 V45
Expert
Expert reply
GMAT 3: 770 Q50 V45
Posts: 1,285
Kudos: 1,906
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
jabhatta2
Hey avigutman - was wondering - could you solve this IR question W/O any calculator ?

I dont think it is possible w/o the calculator, given the closeness of the numbers.
Yes, jabhatta2, I solved it in my head. Here's the thinking I went through:
1. The area of a right triangle is half the product of its legs. Therefore, A=b (granted, the former is a 2-dimensional measurement and the latter is a 1-dimensional measurement, but numerically they're equal).
2. The square of the hypotenuse is equal to the sum of the squares of the legs, so 2^2+A^2 = c^2
3. The hypotenuse MUST be longer than each of the legs, so c MUST be longer than b(=A) --> This eliminates the second option that you were considering, jabhatta2.

Then I went to the first option in the answer choices, and wondered what a A=2 would mean for c. Well, then 8 = c^2 so c is 2*root(2) or approximately 2.8. Done.

I got lucky that the first answer worked out for me, but I would have proceeded with the same strategy as I worked through the remaining answer choices, and I would have used the calculator if I had to. In this case, I didn't have to.
User avatar
mkeshri185
Joined: 01 May 2025
Last visit: 22 Apr 2026
Posts: 110
Own Kudos:
Given Kudos: 2
Posts: 110
Kudos: 8
Kudos
Add Kudos
Bookmarks
Bookmark this Post
What is C here? only two sides of rectangle are B and 2 then what's C it's said it is the lognest side on the boundary. i did not get the image
Sajjad1994
Official Explanation

RO1

The sides of the plot’s boundary that form the right angle of the triangle are 2 km and b km long, and the longest side is c km long. Using the Pythagorean Theorem, \(c^2 = 2^2 + b^2 = 4 + b^2.\) Taking the square root of each side gives \(\sqrt{4+b^2}\). The area of the triangle, A km, can be found using the equation \(\frac{1}{2}(base)(height).\)\(=\frac{1}{2}(b)(2)\) Since A = b, A can be substituted into the previous expression: \(c=\sqrt{4+A^2}\). Using this equation, the value of c can be calculated for each possible value of A. The table below shows the calculations, rounded to the nearest tenth:
Attachment:
3.jpg

The only one of these values of c that is among the options given is 2.8.

The correct answer is 2.8.

RO2

As shown in the table provided in the analysis for RO1, c = 2.8 corresponds to A = 2.0.

The correct answer is 2.0.
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 22 Apr 2026
Posts: 109,754
Own Kudos:
Given Kudos: 105,823
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,754
Kudos: 810,663
Kudos
Add Kudos
Bookmarks
Bookmark this Post
mkeshri185
What is C here? only two sides of rectangle are B and 2 then what's C it's said it is the lognest side on the boundary. i did not get the image

The plot of land forms a right triangle because two perpendicular roads create the boundary. One road is 2 km long, and the other is b km long. These two sides of the triangle form the right angle (90 degrees). The longest side of the triangle, which is opposite the right angle, is the hypotenuse, and that's denoted as c. This hypotenuse is the boundary along the diagonal, connecting the ends of the two roads.



Attachment:
GMAT-Club-Forum-d9wexc2r.png
GMAT-Club-Forum-d9wexc2r.png [ 8.02 KiB | Viewed 2082 times ]
User avatar
GMATINATOR9000
Joined: 23 Feb 2026
Last visit: 22 Apr 2026
Posts: 4
Own Kudos:
Given Kudos: 13
Location: Germany
Schools: LBS
Schools: LBS
Posts: 4
Kudos: 1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
this question shouldn't be relevant for Focus Edition, right?
Bunuel

The plot of land forms a right triangle because two perpendicular roads create the boundary. One road is 2 km long, and the other is b km long. These two sides of the triangle form the right angle (90 degrees). The longest side of the triangle, which is opposite the right angle, is the hypotenuse, and that's denoted as c. This hypotenuse is the boundary along the diagonal, connecting the ends of the two roads.



Attachment:
GMAT-Club-Forum-d9wexc2r.png
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 22 Apr 2026
Posts: 109,754
Own Kudos:
810,663
 [1]
Given Kudos: 105,823
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,754
Kudos: 810,663
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
GMATINATOR9000
this question shouldn't be relevant for Focus Edition, right?



Check these two topics:

  1. GMAT Syllabus for Focus Edition
  2. Geometry Tested on GMAT Focus?

While specific geometry knowledge is not tested on GMAT Focus, not everything involving shapes, volumes, or areas requires specialized geometry knowledge. The area of a square or rectangle, the volume of a cube or rectangular solid, and the Pythagorean theorem are not considered specific geometry knowledge by the GMAT and can still be tested. Moreover, a question can involve shapes but test another area, such as combinations or other topics. There are several questions involving these concepts in the GMAT Prep Focus mocks

The chapter on coordinate geometry, including planes and slopes, is still present in the recent Official Guides. That said, it is tested to a much smaller extent. For example, you might see some questions involving graphs, either in Problem Solving or in Data Insights graph-based questions. However, those usually fall under the functions category rather than pure coordinate geometry, so they typically won’t involve distance calculations, angles, or similar topics.
Moderators:
Math Expert
109754 posts
498 posts
212 posts