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Sajjad1994
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A => 30 % , 50% or 70%
B=> 20% , 40% and 60%

lets say , y% of A is mixed with z% of B to get the 50% in the combined reagent.

She has twice as much of Brand B as Brand A.­

Hence , we get y + 2z= 150

lets try different values of z and y.
If z = 60 , then 30 + 120 = 150 
But there is no value of y as 30. Hence z cant be 60.

Lets take  y=70 and z=40 , 70 + 40*2 = 150 
 It works and is the answer. ( Keep trying only with the 6 values given i.e 30 , 50 , 70 , 20 , 40 and 60 ).

GMATinsight chetan2u KarishmaB Am I right in my approach ?­
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cheshire
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Yep this is correct. Your diagram is similar to the alligation method which might be faster but this is a good approach.
sayan640
A => 30 % , 50% or 70%
B=> 20% , 40% and 60%

lets say , y% of A is mixed with z% of B to get the 50% in the combined reagent.

She has twice as much of Brand B as Brand A.­

Hence , we get y + 2z= 150

lets try different values of z and y.
If z = 60 , then 30 + 120 = 150
But there is no value of y as 30. Hence z cant be 60.

Lets take y=70 and z=40 , 70 + 40*2 = 150
It works and is the answer. ( Keep trying only with the 6 values given i.e 30 , 50 , 70 , 20 , 40 and 60 ).

GMATinsight chetan2u KarishmaB Am I right in my approach ?­
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Good question, my learning is to not fixate and start eliminating, as my first thought was since its 50% net, A must be less which is incorrect
Sajjad1994
A lab assistant at Wizard Labs, a leading chemistry research facility, is mixing a new batch of reagent for the upcoming experiment. She has access to Brand A, which comes in 30%, 50%, and 70% concentrations, and to Brand B, which comes in 20%, 40%, and 60% concentrations. She has an equal amount of each concentration for a given brand (the same amount at 30%, 50%, and 70% for A, for example), but she has twice as much of Brand B as Brand A. Once she picks the proper concentrations, she will use the entire amount of each, but only one concentration of each brand is used.

In the table below, select the concentration of Brand A and of Brand B to be used to create a reagent that is 50% concentrated.­
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Take A = 100 and B = 200. Total quantity = 300.

Required reagent = 50% × 300 = 150.

Check the options:
A = 50% → contributes 50, so B must contribute 100 → B = 50%. Not an option.
A = 70% → contributes 70, so B must contribute 80 → 80/200 = 40%. Valid.

Therefore, A = 70% and B = 40%.
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