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09 Jul 2026, 08:00
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Group 2 but not Group 3: Daria
Any Group: Elise
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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16%
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wrong
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A company is assigning 6 interns, Anya, Bram, Clara, Daria, Elise, and Felix, to 3 orientation groups based on age. The 2 oldest interns will be assigned to Group 1, the 2 youngest interns will be assigned to Group 3, and the remaining 2 interns will be assigned to Group 2. No two interns are the same age. Exactly 3 of the interns are siblings.
The following information is known:
• Bram is older than Daria.
• Daria is older than each of the 3 siblings.
• Elise is not one of the siblings.
Select for Group 2 but not Group 3 an intern who could be in Group 2 but could not be in Group 3, and select for Any Group an intern who could be in any one of the 3 groups. Make only two selections, one in each column.
The following information is known:
• Bram is older than Daria.
• Daria is older than each of the 3 siblings.
• Elise is not one of the siblings.
Select for Group 2 but not Group 3 an intern who could be in Group 2 but could not be in Group 3, and select for Any Group an intern who could be in any one of the 3 groups. Make only two selections, one in each column.
| Group 2 but not Group 3 | Any Group | |
| Anya | ||
| Bram | ||
| Clara | ||
| Daria | ||
| Elise | ||
| Felix |
ShowHide Answer
Official Answer
Group 2 but not Group 3: Daria
Any Group: Elise
|
⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.
I31-50
09 Jul 2026, 09:00
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GMAT Club Official Solution:
A company is assigning 6 interns, Anya, Bram, Clara, Daria, Elise, and Felix, to 3 orientation groups based on age. The 2 oldest interns will be assigned to Group 1, the 2 youngest interns will be assigned to Group 3, and the remaining 2 interns will be assigned to Group 2. No two interns are the same age. Exactly 3 of the interns are siblings.
The following information is known:
• Bram is older than Daria.
• Daria is older than each of the 3 siblings.
• Elise is not one of the siblings.
Select for Group 2 but not Group 3 an intern who could be in Group 2 but could not be in Group 3, and select for Any Group an intern who could be in any one of the 3 groups. Make only two selections, one in each column.
Daria is older than each of the 3 siblings, so Daria is not one of the siblings.
Bram is older than Daria, so Bram also cannot be one of the siblings, because all 3 siblings are younger than Daria.
Elise is not one of the siblings.
Therefore, the 3 siblings must be Anya, Clara, and Felix.
So the age relationships are:
Bram > Daria > Anya
Bram > Daria > Clara
Bram > Daria > Felix
Daria is older than Anya, Clara, and Felix. Therefore, at least 3 interns are younger than Daria. Since Group 3 contains only the 2 youngest interns, Daria cannot be in Group 3.
Daria can be in Group 2. For example:
Bram > Elise > Daria > Anya > Clara > Felix
So Daria could be in Group 2 but could not be in Group 3.
Now consider Elise. Elise has no fixed age relationship with any other intern, so Elise can be placed in any group.
Elise in Group 1:
Elise > Bram > Daria > Anya > Clara > Felix
Elise in Group 2:
Bram > Daria > Elise > Anya > Clara > Felix
Elise in Group 3:
Bram > Daria > Anya > Clara > Felix > Elise
So Elise could be in any one of the 3 groups.
Why the other choices do not work:
Bram must be older than Daria and the 3 siblings, so Bram cannot be in Group 2 or Group 3.
Anya, Clara, and Felix each have at least Bram and Daria older than them, so none of them can be in Group 1. Therefore, none of them fits Any Group.
Also, each of Anya, Clara, and Felix could be in Group 3, so none of them fits Group 2 but not Group 3.
Answer:
Group 2 but not Group 3: Daria
Any Group: Elise
GMAT-Club-Forum-dhdxtkwq.png [ 14.1 KiB | Viewed 1667 times ]
A company is assigning 6 interns, Anya, Bram, Clara, Daria, Elise, and Felix, to 3 orientation groups based on age. The 2 oldest interns will be assigned to Group 1, the 2 youngest interns will be assigned to Group 3, and the remaining 2 interns will be assigned to Group 2. No two interns are the same age. Exactly 3 of the interns are siblings.
The following information is known:
• Bram is older than Daria.
• Daria is older than each of the 3 siblings.
• Elise is not one of the siblings.
Select for Group 2 but not Group 3 an intern who could be in Group 2 but could not be in Group 3, and select for Any Group an intern who could be in any one of the 3 groups. Make only two selections, one in each column.
Daria is older than each of the 3 siblings, so Daria is not one of the siblings.
Bram is older than Daria, so Bram also cannot be one of the siblings, because all 3 siblings are younger than Daria.
Elise is not one of the siblings.
Therefore, the 3 siblings must be Anya, Clara, and Felix.
So the age relationships are:
Bram > Daria > Anya
Bram > Daria > Clara
Bram > Daria > Felix
Daria is older than Anya, Clara, and Felix. Therefore, at least 3 interns are younger than Daria. Since Group 3 contains only the 2 youngest interns, Daria cannot be in Group 3.
Daria can be in Group 2. For example:
Bram > Elise > Daria > Anya > Clara > Felix
So Daria could be in Group 2 but could not be in Group 3.
Now consider Elise. Elise has no fixed age relationship with any other intern, so Elise can be placed in any group.
Elise in Group 1:
Elise > Bram > Daria > Anya > Clara > Felix
Elise in Group 2:
Bram > Daria > Elise > Anya > Clara > Felix
Elise in Group 3:
Bram > Daria > Anya > Clara > Felix > Elise
So Elise could be in any one of the 3 groups.
Why the other choices do not work:
Bram must be older than Daria and the 3 siblings, so Bram cannot be in Group 2 or Group 3.
Anya, Clara, and Felix each have at least Bram and Daria older than them, so none of them can be in Group 1. Therefore, none of them fits Any Group.
Also, each of Anya, Clara, and Felix could be in Group 3, so none of them fits Group 2 but not Group 3.
Answer:
Group 2 but not Group 3: Daria
Any Group: Elise
Attachment:
GMAT-Club-Forum-dhdxtkwq.png [ 14.1 KiB | Viewed 1667 times ]
General Discussion
vrinda6
Joined: 20 Jul 2020
Last visit: 05 Sep 2026
Posts: 65
Given Kudos: 17
Location: India
Schools: Booth '27 Kellogg '27 CBS '27 Duke '27 Haas '27 HBS '27 Ross '27 Stern '27 Stanford '27 Wharton '27 Anderson '27
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Schools: Booth '27 Kellogg '27 CBS '27 Duke '27 Haas '27 HBS '27 Ross '27 Stern '27 Stanford '27 Wharton '27 Anderson '27
Posts: 65
09 Jul 2026, 08:10
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1. DARIA is older than her siblings,
2. BRAM is olfer than Daria, that means Bram is not one of the sbilings
3.ELISE is not a sibling.
Only possible siblings of Daria could be Anya, Felix and Clara.
Since Bram is older than Daria, and by extension now Anya, Felix and Clara.
Bram - G1 only
Daria- G2 OR G1
Anya- G2 OR G3
Felix- G2 OR G3
Elise- G1 OR G2 OR G3
Clara-G2 OR G3
HENCE
DARIA FOR G2 BUT NOT G3
ELISE Can be anywhere.
2. BRAM is olfer than Daria, that means Bram is not one of the sbilings
3.ELISE is not a sibling.
Only possible siblings of Daria could be Anya, Felix and Clara.
Since Bram is older than Daria, and by extension now Anya, Felix and Clara.
Bram - G1 only
Daria- G2 OR G1
Anya- G2 OR G3
Felix- G2 OR G3
Elise- G1 OR G2 OR G3
Clara-G2 OR G3
HENCE
DARIA FOR G2 BUT NOT G3
ELISE Can be anywhere.
