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Q1 When the boy is 8 m from the lamppost, he casts a shadow that is__________m long.

answer is A)2
A. 2
B. 2.25
C. 2.50
D. 2.75
E. 3


SOLUTION : FROM similar triangles we have , lets say shadow is x then x/(8+x) = 1.6/8

so 8x= 1.6*8 + 1.6x

6.4x= 1.6 *8

x= 2

answer is A) 2


Q2When the boy casts a shadow that is 3 m long, he is__________m from the lamppost.

ANSWER IS A)12
A. 12
B. 9
C. 10
D. 11
E. 13

FROM similar triangles sides proportionality we have , lets say distance from lamppost = x than 3/(x+3 ) =1.6/8

so 24 = 1.6*3 +1.6x
1.6x= 24 -4.8
1.6x= 19.2

x= 12

so answer is A)12
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Given
the height of the boy = 1.6 m (constant)
and
1.6/8 = 1.5/(6+1.5)

when the boy is 7m from the lamppost
1.6/8 = 1.75/(7+1.75)

When the boy is 8 m from the lamppost , let the shadow be s meter.
1.6/8 = s/(8+s)
8/s =4
s = 2

When the boy casts a shadow of 3 m , let he is d meter away from the post
1.6/8 = 3/(3+d)
d/3 = 4
d = 12

Thus,
When the boy is 8 m from the lamppost, he casts a shadow that is__________m long.
A. 2

When the boy casts a shadow that is 3 m long, he is__________m from the lamppost.
A. 12
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Case1: When the boy is 6m away the shadow is 1.5
Also given - \(\frac{8}{1.6}\) = \(\frac{(6+1.5)}{1.5}\) = => \(\frac{8}{1.6}\)=\(\frac{7.5}{1.5}\)
Where,
8=Post Height
1.6=Boy Height
6=Boy Distance form the post
1.5=Shadow height

Case2: When the boy is 7m away the shadow is 1.75
Also given - \(\frac{8}{1.6}\) = \(\frac{(7+1.75)}{1.75}\) = => \(\frac{8}{1.6}\)=\(\frac{8.75}{1.75}\)
Where,
8=Post Height
1.6=Boy Height
7=Boy Distance form the post
1.75=Shadow height

From Case1 & Case2, we can infer that the Ratio of the Sum of (distance of the boy From the post + length of the shadow) to the length of the shadow
will always be 5:1

When the boy is 8 m from the lamppost, he casts a shadow that is__________m long.
Let the shadow length be x
So, as per above reasoning,
\(\frac{(8+x)}{x}\) = 5 => 8+x = 5x => 8 = 4x =>x=2

IMO Option A

When the boy casts a shadow that is 3 m long, he is__________m from the lamppost.
Let the distance from the post be y
So, as per above reasoning,
\(\frac{(y+3)}{3}\) = 5 => y+3 = 15 => y=12

IMO Option A

Option A for Both
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OA to this question is 2 for first blank and 12 for the second. It is an easy question overall, Excellent work by rocky620
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Instead of putting the solution in the equation, can we solve this using unitary method?
If 7m is 1.75, then i can calculate for 8m and also for the second ques using this method.

The answer that i am getting is same­
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can i not simply say that if at 6m, the shadow is 1.5 and at 7m, its 1.75, then a difference pattern is seen and i can add 0.25 to find the dropdown answers?
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@bunuel can i not simply say that if at 6m, the shadow is 1.5 and at 7m, its 1.75, then a difference pattern is seen and i can add 0.25 to find the dropdown answers?
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riyamakwana_
@bunuel can i not simply say that if at 6m, the shadow is 1.5 and at 7m, its 1.75, then a difference pattern is seen and i can add 0.25 to find the dropdown answers?
The length of post by boys height is a constant 8/1.6=5

5 = (d from post + shadow length) / shadow length

This can be inferred from given equation.
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