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805+ (Hard)|   Graphs|      
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The graph shows the percentage of children in particular grade levels 25 Nov 2023, 04:22
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Dropdown 1: 15 Dropdown 2: were two grade levels
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

95% (hard)

Question Stats:

34% (03:36) correct 66% (03:36) wrong based on 360 sessions

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The graph shows the percentage of children in particular grade levels that participated in the six afterschool activities offered by a school in 2017. No child was allowed to participate in more than one sport activity (soccer, tennis, track) or more than one non-sport activity (math team, band, debate team) but children were allowed to participate in one activity from each category (sport or non-sport). Every child had to participate in at least one of the six activities.

For each of the following, use the drop-down menu to create the most accurate statement on the basis of the chart:

Approximately percent of 8th graders in 2017 participated in exactly one of the six after-school activities.

In 2017 there in which more students participated in sport activities than non-sport activities.


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Dropdown 1: 15 Dropdown 2: were two grade levels
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The graph shows the percentage of children in particular grade levels 01 Dec 2023, 08:20
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Official Explanation

In 2017 there __________ in which more students participated in sport activities than non-sport activities.

Explanation

For the last prompt, you need to go through all of the data. For each grade level you need to estimate the two categories and see which one is greater. Visually, you should isolate the two different groups and look for years in which the non-sport activities were particularly low. From the first prompt, you know that 8th grade is one grade level in which more students participated in sport activities than non-sport activities (by 95% to 90%). In 7th grade, 100% of students participated in non-sport activities, so this statement is not true for that grade. 9th grade can be quickly eliminated as well, because only 70% of students participated in sport activities. In 10th and 11th grade, the data is fairly similar and in both cases more students participated in non-sport activities by a decent margin. However, in the 12th grade year it is clear from the charts that there was a substantial change: only about 80% of students participated in non-sport activities while nearly 100% participated in sport activities. As a result, the correct answer is (C) as there were two grade levels in which the statement is true.
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The graph shows the percentage of children in particular grade levels 22 Dec 2024, 11:48
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for the 1st one, why is it not 20%? as per graph, 20% (purple line) of the of 8th graders in 2017 participated in Math team.
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The graph shows the percentage of children in particular grade levels 15 Jan 2025, 02:52
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ravitejab1
for the 1st one, why is it not 20%? as per graph, 20% (purple line) of the of 8th graders in 2017 participated in Math team.
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Adding all the percentages in the 8th grade will be equal to 185 percent, now, any student can take part in either one or maximum of two activities, so adding 185 percent, adds the students taking part in two activities twice.
Hence 185 - ( students taking part in 2 activiites)= 100,
so, students taking part in two activities = 85 percent , and , hence students taking part in only one activity is 15 percent, as it is mandatory for a student to take part in atleast one of the activities,
Hope u understood, this requires a fundamental understanding of overlapping sets concept.
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The graph shows the percentage of children in particular grade levels 09 Jul 2025, 05:26
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Q1.
From the 8th Grade data on the graph:

Sport activities:
Soccer: ~45%
Tennis: ~25%
Track: ~25%
Total sport participation: 45 + 25 + 25 = 95%
Non-sport activities:
Math team: ~20%
Band: ~55%
Debate: ~15%
Total non-sport participation: 20 + 55 + 15 = 90%
Let’s assume 100 total students in 8th grade
using overlapping sets
Students in both categories = Sport % + Non-sport % - 100% = 95% + 90% - 100% = 85%( (since everyone must do at least one activity)
Students in exactly one activity = 100% - 85% = 15%
Answer: Approximately 15 percent

Q2)

Visual Pattern Recognition
Look for grades where sports lines are generally higher than non-sports lines & for this focus on dominant activities

Sports: Soccer (red) is usually highest
Non-sports: Band (teal) is usually highest
you can quickly eliminate all the grade except for 8 & 12th grade which are quite close. Hence verify these 2 only.
8th: Sports ~95%, Non-sports ~90% → Sports win
12th: Sports ~98%, Non-sports ~77% → Sports win

Answer: were two grade levels

Key insight: For comparison questions, identify the dominant elements first, then calculate only the borderline cases.
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The graph shows the percentage of children in particular grade levels 20 Oct 2025, 22:18
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you approach to identify dominant is unclear here. Could you please how you eliminated the other grades and come down to 10th and 12th?
Mannisha
Q1.
From the 8th Grade data on the graph:

Sport activities:
Soccer: ~45%
Tennis: ~25%
Track: ~25%
Total sport participation: 45 + 25 + 25 = 95%
Non-sport activities:
Math team: ~20%
Band: ~55%
Debate: ~15%
Total non-sport participation: 20 + 55 + 15 = 90%
Let’s assume 100 total students in 8th grade
using overlapping sets
Students in both categories = Sport % + Non-sport % - 100% = 95% + 90% - 100% = 85%( (since everyone must do at least one activity)
Students in exactly one activity = 100% - 85% = 15%
Answer: Approximately 15 percent

Q2)

Visual Pattern Recognition
Look for grades where sports lines are generally higher than non-sports lines & for this focus on dominant activities

Sports: Soccer (red) is usually highest
Non-sports: Band (teal) is usually highest
you can quickly eliminate all the grade except for 8 & 12th grade which are quite close. Hence verify these 2 only.
8th: Sports ~95%, Non-sports ~90% → Sports win
12th: Sports ~98%, Non-sports ~77% → Sports win

Answer: were two grade levels

Key insight: For comparison questions, identify the dominant elements first, then calculate only the borderline cases.



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