chetan2u
Is a + b > 0?
(1) |a| > |b|
(2) a < b
Self made - tricky
Number line
(1) |a| > |b|
The distance of a from 0 is more than the distance of b from from 0.
Both a and b could be positive...Yes
Both could be negative....No
(2) a < b
Both a and b could be positive...Yes
Both could be negative....No
Combined
a<b means that a should be closer to 0, if a and b are positive. But we know that a is farther from 0 from statement I. Hence a is surely negative.
Now, a is negative and farther from 0, whatever be b, the sum a+b will be less than 0 as |a| has a higher value.
Algebraic
(1) |a| > |b|
As both sides are positive, we can square the two sides
\(|a|^2 > |b|^2...............a^2>b^2....a^2-b^2>0.......(a+b)(a-b)>0\)
Nothing more as a+b will depend on a-b.
(2) a < b
\(a-b<0\)
Nothing about a+b
Combined
\((a+b)(a-b)>0\), so a+b and a-b will have same sign.
a-b<0, so a+b is also less than 0.
Answer is NO
C