|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
HoneyLemon
Updated on: 08 Jun 2020, 00:15
Originally posted by HoneyLemon on 07 Jun 2020, 17:57.
Last edited by Bunuel on 08 Jun 2020, 00:15, edited 1 time in total.
Last edited by Bunuel on 08 Jun 2020, 00:15, edited 1 time in total.
Renamed the topic.
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
57% (01:43) correct
43%
(02:02)
wrong
based on 103
sessions
History
Date
Time
Result
Not Attempted Yet
Is x > y?
(1) x + y < 0
(2) x + |y| < −1
(1) x + y < 0
(2) x + |y| < −1
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
07 Jun 2020, 21:47
Kudos
Bookmarks
DasAshishAshutosh
Question: Is x > y?
Statement 1: (1) x + y < 0
i.e. x < -y
@y = -10, x = 5 i.e. x > y
@y = 10, x = -11 i.e. x < y
NOT SUFFICIENT
Statement 2: x + |y| < −1
i.e. Since lyl is non-negative therefore x is definitely negative because their sum is negative
ALso, Absolute value of x is greater than absolute value of y with an amount greater than 1
hence for both positive and negative value of y
x < y
SUFFICIENT
Answer: Option B
07 Jun 2020, 23:57
Kudos
Bookmarks
DasAshishAshutosh
Analyze statement 1 alone
(1) x + y < 0
Inference:
(a) Both x and y are negative=> (-2,-3)
(b) x is negative and y is positive => (-5,2)
(c) x is positive and y is negative => ( 3, -4)
Statement (1) alone not sufficient
Analyze statement 2 alone
(2) x + |y| < −1
Inference:
For the expression to be negative
As |y| is always +ve => x is always negative
Absolute value of x is always greater than absolute value of y.
(a) x is negative and y is +ve=> ( -3,1)
(b) x is negative and y is negative=> (-3,-1)
Thus, X is always less than y.
Statement 2 alone is sufficient
Answer: B
[/highlight]
