Consider a ten-digit integer A,BC6,7DE,000. Is the integer divisible

Question

Consider a ten-digit integer A,BC6,7DE,000. Is the integer divisible by 32?

(1) Three-digit integer ABC = 253
(2) Two-digit integer DE = 13

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Nevernevergiveup · Answer

32 is not but 2^5 so have 3 zeros(tens) and a 6 to get divided by 4 2s so just need A where we have one more 2 in 253

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Deepakjhamb · Answer

Integer is divisible by 32 if last 5 digits are divisible by 32

Statement 1 : last 5 digits not known so insufficient

Statement 2 : last 5 digits known so sufficient as de = 13

So ans is b

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Deepakjhamb · Answer

32 is not but 2^5 so have 3 zeros(tens) and a 6 to get divided by 4 2s so just need A where we have one more 2 in 253

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Seems ur analysis is wrong

See for dovisibility by 2 last number should be divisible by 2 , for divisibility by 4 last 2 digits and thus by 32 last 5 digits

So until u know DE u cannot be sure

akadiyan · Answer

Consider a ten-digit integer A,BC6,7DE,000. Is the integer divisible by 32?

Note:
Divisibility rule for 32 - If the last 5 digits of a number should be divisible by 32, then the whole number is divisible by 32.

(1) Three-digit integer ABC = 253
We do not know any information about DE.
Option 1 -  Insufficient.

(2) Two-digit integer DE = 13
This option gives us DE from which we can calculate the last 5 digits of the number and then we can find whether the number is divisible by 32 .

Option 2 -  Sufficient.

Ans   B

GCMEMBER · Answer

Consider a ten-digit integer A,BC6,7DE,000. Is the integer divisible by 32?

For an integer to be divisible by 32, last 5 digits should be divisible by 5.

(1) Three-digit integer ABC = 253
Last 5 digits not known.
Not sufficient

(2) Two-digit integer DE = 13
Last 5 digits known
Sufficient

Option B

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CEdward · Answer

The answer is B.
Statement 1 : Insufficient b/c this is a ridiculous proposition to ask one to divide a 10 digit number by 32. What is easy to hone in on is DE (which we can see by the presence of 3 0s). DE can be a multiple of 32 or not. So the integer may or may not be divisible by 32.
e.g. DE = 32 then yes
e.g. DE = 33 then no
Statement 2: Following from the logic of the previous statement we see that DE = 13.
13/32 is not an integer. 
Sufficient.

Nevernevergiveup · Answer

yup you are right. thanks

chetan2u · Answer

Divisibility by 2 and it’s power depend on the number of digits equal to the power. 
2^1 : look for divisibility of one digit by 2
2^2 : look for divisibility of two digits ( ones and tens) by 4.
So 32 or 2^5 will depend on last 5 digits from right. 
A,BC6,7DE,000.
Last 3 0s tell us that it is divisible by 2^3, but for 2^5, we have to look for divisibility of DE,000 by 32.

Statement II gives us the value of DE, so we can find divisibility of 13000 by 32 and whatever be the answer will be the answer for divisibility of the entire term by 32.

B

unraveled · Answer

Consider a ten-digit integer A,BC6,7DE,000. Is the integer divisible by 32?

32 = 2^5  
 A,BC6,7DE,000 = A,BC6,7DE * 1,000 = A,BC6,7DE * (10)^3 = A,BC6,7DE * 2^3 * 5^3 
Thus, 
A,BC6,7DE,000 is divisible by  2^3

Hence, we need to check whether A,BC6,7DE is divisible by  2^2 = 4 
 \implies  we need to check only the last two digit(DE) of A,BC6,7DE for divisibility by 4.

(1) Three-digit integer ABC = 253
DE may or may not be divisible by 4

INSUFFICIENT.

(2) Two-digit integer DE = 13
13 is not divisible by 4.

SUFFICIENT.

Answer B.

exc4libur · Answer

32=2^5
abc67de*1000 is div if we have 5 two's (2)
1000=10^3 has 2^3
find if abc67de is div by 2^2

(1) insuf

(2) sufic

abc6713 is not even

(B)

bumpbot · Answer

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Consider a ten-digit integer A,BC6,7DE,000. Is the integer divisible

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