Bunuel
What is the units' digit of 76^k, where k is an integer ?
(1) k is a prime number
(2) k is greater than 2
ANSWER: D
This question tests knowledge of number properties.
the units digit of a non-decimal number is the right-most digit of a number before you get to the decimal point.
since k is an integer,
units digit of 76^k could be 0, 1, or 6 depending on whether k is negative, 0, or postive respectively. 1:
any prime number is positive number, hence we can tell with certainty that the unit digit is 6. you can try multiplying 76 by itself as much as u can and you find out the unit digit doesnt change. in the exam it's easy to recall that 6 to any positive index yields a unit digit of 6. 6*6 = 36 etc..
So 1 is SUFFICIENT
2: k being greater than 2 means that unit digit of 76^k is 6; if you follow the logic given above. So 2 is also SUFFICIENT. Each of 1 and 2 is SUFFICIENT.