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He covered x and has y to go. We know

x+y= 24 and x=5/7y

so he covered x=10km=10000m in 100min=6000sec

Therefore speed = 10000/6000 = 10/6 = 1,66

Correct answer is E
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Let the distance he covered be x. Remaining distance = 24-x
x = 5(24-x)/7
7x = 120 - 5x
x = 10
Time taken to cover 10km = 1hr40 mins = 5/3hr
Speed in km/hr = 10*3/5 = 6
Speed in m/s = 6*5/18 = 5/3 = 1.66
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total D =24 => 24 = 5/7x+x
(24 = 5/7x+x) * 7
5x+7x=168
x=14
Therefore he covered 5/7 * 14 = 10 miles in 1hr and 40 min
Speed over this period can be expressed as
10km = 10,000 m
1hr40min= 100 min = 6000 sec
Speed = 10000/6000= 1.66 m/s
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gmatbusters
While covering a distance or 24 km, a man noticed that after walking for 1 hour and 40 minutes, the distance covered by him was \(5/7\) of the remaining distance. What was his speed in m/s?
A) 1.12
B) 1.21
C) 1.33
D) 1.55
E) 1.66

Weekly Quant Quiz #6 Question No 8


Good night!

I haven't been able to solve this but after one hour I need to ask you guys:

Where does the following come from?

D=5/7*(24-D)


Kind regards!
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I am absolutely confused by the wording used in problem.
If 24 km distance is covered in 1 hour 40 mins.. then should speed be not as below for m/s
\(\frac{24*1000}{100*60}\)


please help me to understand the problem and solution
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While covering a distance or 24 km, a man noticed that after walking for 1 hour and 40 minutes, the distance covered by him was 5/7 of the remaining distance. What was his speed in m/s?

Let the distance covered by him be d km. So the remaining distance is 24 -d.

Its given that :

\(d = \frac{5}{7}*(24 -d)\)

7d = 120 - 5d
12 d = 120
d = 10 km

A distance of 10 km is covered in 1 hour and 40 mins ( 5/3 hours)
Speed = 10/5/3 = 6 km/hr = 6 * 5/18 m/s = 5/3 = 1.66 m/s ( Multiply by 5/18 to convert from km/hr to m/sec )

Option E is the answer.

Thanks,
Clifin J Francis,
GMAT SME
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