Bunuel
What is \(m + n\) ?
(1) \(2^m*3^n = 648\)
(2) \(|m| + |n| = 7\)
Note nothing was mentioned about m or n so we cannot assume they are integers.
Statement 1:This would have infinitely many solutions however only one solution is an integer solution as \(648 = 8*(75+6) = 8*81 = 2^3*3^4\). Insufficient.
Statement 2:m and n can be both positive or both negative. Insufficient.
Combined:If both m and n were positive then we'd have m = 3 and n = 4 as a solution. We may try finding another solution, assume m is negative while n is positive. Then \(n - m = 7\) and \(n = m + 7\). Try plugging that into the first equation to see if it makes sense, we'd have:
\(2^m *3^{m + 7} = 2^3*3^4\)
\(6^m=2^3*3^4/3^7=(\frac{2}{3})^3\)
Since the result is a fraction, we can confirm m is a negative number. Then n is a number less than 7, so there is a possible second solution. For this solution, we already have n - m = 7 so n + m cannot be 7. Thus the value of m+n is not known. Insufficient.
(The 2nd solution is roughly m = -0.68 and n = 6.32, try plugging that in the first equation with a calculator!)
Ans: E