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What is the area of four sided figure formed by the intersection of

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What is the area of four sided figure formed by the intersection of [#permalink]

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What is the area of four sided figure formed by the intersection of the set of lines represented by |2x| + |y| = 6?

A. 18
B. 24
C. 30
D. 36
E. 48
[Reveal] Spoiler: OA
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Re: What is the area of four sided figure formed by the intersection of [#permalink]

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New post 09 Feb 2015, 05:37
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We need to find the equation |2X| + |Y| = 6

Equation 1 : 2X + Y = 6 which is Y = -2X + 6 . Points where this lines intersects the X and Y axis ( X = 0 , Y = 6 ) , ( X = 3 , Y = 0 )
Equation 2 : -2X - Y = 6 which is Y = -2X - 6 . Points where this lines intersects the X and Y axis ( X = 0 , Y = -6 ) , ( X = -3 , Y = 0 )

From here we know the intersects of the lines ,
Using area of triangles = 0.5 * X * Y
= 0.5 * 3 * 6
= 9
Using symmetry 4 triangles = 9 * 4
= 36 .
Answer is D . ( Sketch a diagram to visualize it helps !! )
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Re: What is the area of four sided figure formed by the intersection of [#permalink]

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New post 30 Jun 2016, 22:50
Is it correct if I assume that the area is the product of the following two equations?

2x+y=6
2x+y=-6
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Re: What is the area of four sided figure formed by the intersection of [#permalink]

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These are four equations. If you carefully observe these equations because of the way mod functions are plotted around y and x axis as opposite images, these four lines form a rhombus with diagonals of lengths as 6 and 12 (if x =0 then possible y values 0,6 and 0,-6) and then (if y =0 x intercepts at 3,0 and -3,0. Area of rhombus is 1/2 * (product of diagonals) = 1/2 * 12 *6 = 36.
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Re: What is the area of four sided figure formed by the intersection of [#permalink]

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New post Updated on: 05 Oct 2016, 13:41
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Turkish wrote:
What is the area of four sided figure formed by the intersection of the set of lines represented by |2x|+|y| = 6?

1. 18
2.24
3.30
4.36
5.48


we just need four XY pair to define the four-sided figure.
Lets works with the concept of X and Y intercepts
When |x|=0; then |y|=6 .. right
y=-6 and 6 ; XY pairs are {0,-6} and {0,6}

when |y|=0 then |2x|= 6
x=-3 and 3 ; The XY pairs are (-3,0 and 3,0)

When you plot these XY pairs you will see that you get a diamond shaped figure (an upright RHOMBUS ) which can be divided into 2 equal triangles. the base of these two triangles is the x-axis

Now area of a triangle = 1/2 * base * height = 1/2 * 6*6 (the distance between -3 and 3 is 6) and the height is 6-0 = 6
Therefore Area of the triangle = \(\frac{1}{2}*36\) =====>18
There are 2 such triangle
Total area = 2*18 =36
ANSWER IS D
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Originally posted by LogicGuru1 on 24 Jul 2016, 23:29.
Last edited by LogicGuru1 on 05 Oct 2016, 13:41, edited 1 time in total.
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Re: What is the area of four sided figure formed by the intersection of [#permalink]

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New post 15 Aug 2016, 05:28
What's the fastest way to solve this?

I took almost 4 mins. First opened mods and found the 4 equations. Then found 2 points per equation. Then found area of one triangle and multiplied it by 4 (for area of the 4 triangles formed)
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Re: What is the area of four sided figure formed by the intersection of [#permalink]

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Turkish wrote:
What is the area of four sided figure formed by the intersection of the set of lines represented by |2x|+|y| = 6?

1. 18
2.24
3.30
4.36
5.48


took me some time to draw some points...
but i believe the easiest way is:
x=0, then y=6 or -6.
y=0, x=3 or -3.
we get 4 similar 90 degrees triangles, with the 90 degree angle at the origin.
short leg is 3, long leg is 6.
area is leg*leg/2 = 18/2 = 9.
since we have 4 of these triangles, the area is 9*4 = 36.

D
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Re: What is the area of four sided figure formed by the intersection of [#permalink]

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New post 19 Aug 2017, 06:20
Can someone give a diagrammatic answer to this? Would be really helpful to understand what kind of rhombus or square gets created :)
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Re: What is the area of four sided figure formed by the intersection [#permalink]

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New post 19 Aug 2017, 06:26
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Madhavi1990 wrote:
What is the area of four sided figure formed by the intersection of the set of lines represented by |2x| + |y| = 6?

A. 18
B. 24
C. 30
D. 36
E. 48


Can someone give a diagrammatic answer to this? Would be really helpful to understand what kind of rhombus or square gets created :)


Check below:
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Re: What is the area of four sided figure formed by the intersection of [#permalink]

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New post 05 Oct 2017, 19:52
Please correct me if i am wrong.

|2x|+|y|=6

When, x=2, y=2,-2 Points are (2,2) and (2,-2)
When, x=-2 y=2,-2 Points are (-2,2) and (-2,-2)

I get a square with an area of (4x4) =16.
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Re: What is the area of four sided figure formed by the intersection of [#permalink]

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New post 05 Oct 2017, 21:02
Expert's post
Rishovnits wrote:
Please correct me if i am wrong.

|2x|+|y|=6

When, x=2, y=2,-2 Points are (2,2) and (2,-2)
When, x=-2 y=2,-2 Points are (-2,2) and (-2,-2)

I get a square with an area of (4x4) =16.


It's a rhombus. Check here: https://gmatclub.com/forum/what-is-the- ... l#p1910705
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What is the area of four sided figure formed by the intersection of [#permalink]

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New post 06 Oct 2017, 14:26
From the equation, we know that for all the four lines:
y-intercept is either +6 or -6
&
x-intercept is either +3 or -3

So, the shape of the quadrilateral is a rhombus with one diagnol length as 12 (from +6 to -6) and other diagnol length as 6 (from +3 to -3)

Therefore, Area of Rhombus= (d1xd2)/2 = (12x6)/2 = 36.

Ans D.

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What is the area of four sided figure formed by the intersection of [#permalink]

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New post 12 Apr 2018, 14:54
Turkish wrote:
What is the area of four sided figure formed by the intersection of the set of lines represented by |2x| + |y| = 6?

A. 18
B. 24
C. 30
D. 36
E. 48


By drawing a diagram we see that we have a rhombus .We know that each side of the rhombus is X so \(Area=base*hight=x^2\) must be a perfect square of a number D. \(36=6^2\) fits
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What is the area of four sided figure formed by the intersection of   [#permalink] 12 Apr 2018, 14:54
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