What is the area of the region enclosed by lines y=x, x=y,

Question

m22 q20

What is the area of the region enclosed by lines  y=x ,  x=-y , and the upper crescent of the circle  y^2+x^2=4  ?

A.  \frac{\pi}{4}

B.  \frac{\pi}{2}

C.  \frac{3\pi}{4}

D.  \pi

E.  4\pi

Bunuel · Accepted Answer

m22 q20

What is the area of the region enclosed by lines \(y=x\), \(x=-y\), and the upper crescent of the circle \(y^2+x^2=4\) ?

A. \(\frac{\pi}{4}\)
B. \(\frac{\pi}{2}\)
C. \(\frac{3\pi}{4}\)
D. \(\pi\)
E. \(4\pi\)

The circle represented by the equation \(x^2+y^2 = 4\) is centered at the origin and has the radius of \(r=\sqrt{4}=2\).

Look at the diagram below:

We need to find the area of the upper crescent, so the area of the yellow sector. Since the central angle of this sector is 90 degrees then its area would be 1/4 of that of the circle (since circle is 360 degrees).

The area of the circle is \({\pi}{r^2}=4\pi\), 1/4 of this value is \(\pi\).

Answer: D.

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Attachment:

m22-20.png [ 16.59 KiB | Viewed 14311 times ]

Zarrolou · Answer

y^2+x^2=4  is a circle with its center in the origin (0,0)
The lines  y=x  and  y=-x  intersect in (0,0) and form an angle of 90° between them.
The area of the circle is  r^2PI=4PI , now we are looking for "area of the region enclosed by lines y=x, x=−y, and the upper crescent of the circle y^2+x^2=4", which can be found through this equation  4PI : 360=x : 90  (Tot area : Tot angle = x : angBetweenLines)
D  x=PI

doe007 · Answer

The lines y=x, x=−y intersecting at (0,0) and they are perpendicular to each other. 
The circle y^2+x^2=4 is centered at (0,0) and has a radius of 2.
These two lines are dividing the circle y^2+x^2=4 into four equal segments. 
Area of each segment = (PI*r^2) / 4 = (PI*2^2) / 4 = PI

Answer is D.

kamalahmmad1 · Answer

Hi Bunuel,
in the above problem, i understand that the circle is centered at the origin and has radius 2 but lines y=x, and x = -1 represents the half of the circle so the area enclosed should be half of the total area, I mean 4pi/2. i know, i am missing something, please clarify!
and How do I know that question asks the area of upper 1/4 of the area or How do i determine the 90 degree portion??

nt2010 · Answer

kamalahmmad1

Two lines are perpendicular if their slopes are -ve reciprocal of each other. E.g. line 1 : y = mx and line 2: y = (-1/m)x then line 1 and line two are perpendicular

Here y = x and y = -x meet the above stated criteria for perpendicular lines

//kudos please, if the above explanation is good.

Bunuel · Answer

The two lines are y=x and y=-x (x=-y), not x = -1. Both lines are shown on the diagram in my post.

Lines y=x and y=-x make 90 degrees.

jayaddula · Answer

To find the Area of a sector

Arc angle Area of sector
___________ = ______________ 
360 Area of circle

90 Area of sector
___ = _____________
360 4 Pi

Area of sector = 4 pi x 90/ 360 = pi

Asifpirlo · Answer

...
My solution(with detail explanation):
This diagram is indispensable:

mridupawandas · Answer

All the 3 parts i.e x=y; x=-y; and x^2+y^2=4 makes one forth of the circular region x^2+y^2=4 area of which is 4pi so the required area is pi. hope this one makes it clear.

umasarath52 · Answer

Question corrected!

Circle is y^2+x^2=4 has radius 2. Area of circle = pi * 4
y=x is the line that passes through 1 and 3 quadrants which has 45 degree to x-axis.
y=-x is the line that passes through 2 and 4 quadrants which has 45 degree to x-axis.

The two lines, divides the circle into 4 parts.

Combining all the three, (question to find the area of the upper crescent) Area = 4 pi/4 = pi

sajib2126 · Answer

Why or How does Circle is y^2+x^2=4 has radius 2 ?

umasarath52 · Answer

In the equation x^2+y^2=4

all the points (2,2)(-2,2)(0,2)(2,0) are on the circle. And these have the center as (0,0)

Hence the radius is 2.

Another explanation: 
Equation Of A Circle
(x - a)^2 + (y - b)^2 = r^2
where
a is the x co-ordinate of the centre of the circle
b is the y co-ordinate of the centre of the circle
r is the radius of the circle

Comparing the above equation with the equation (x-0)^2+(y-0)^2=4
r^2 = 4
r=2

center is (0,0)

testcracker · Answer

hi the area of the circle is represented by the equation, x^2 + y^2 = 4, means that the area of the circle is x^2 + y^2 = 4 now, as 2 sides are equal to each other, it can be said that area is (x^2 + y^2) OR 4 since area is 4, the radius is 2 I don't know whether this reasoning is okay, but I have seen the scenario this way Expert's reply on this issue is highly desired thanks ???

ujjwal80 · Answer

Hi  Bunuel , I was able to solve this question but it took me a while to visualise the diagram. So just asking by curiosity, can we expect this type of questions in GMAT? As always appreciate your efforts in advance! Thanks

Bunuel · Answer

Yes, I think it's a perfectly valid question. Notice that the average time it took users to answer it correctly is just 1:07 minutes.

testcracker · Answer

hi as far as time is concerned, you can see the problem this way (y =x), means slope is 1 and the line passes through the origin (y = -x), means slope is -1, and the line passes through the origin now it is worth noticing that a slope of 1 or -1 creates an angle of 45 degree, so 2 slopes jointly cover a 90 degree also, when 2 lines are perpendicular to each other, their slopes are negative reciprocal to each other here 1 is negative reciprocal to -1, so the slopes are perpendicular to each other, creating an angle 90 degree thus, 2 slopes together add to 90 degrees, which is 1/4 of pi (2)^2 , as the radius is 2 we get from (x^ + Y^ = 4) OR you can simply draw the 2 slopes to see the area covered by the upper crescent hope this helps and is clear! thanks and cheers!

ujjwal80 · Answer

Thanks,  gmatcracker2018 , I will keep your explanation in mind next time I see such question.

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What is the area of the region enclosed by lines y=x, x=y,

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