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What is the area of parallelogram ABCD ?

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What is the area of parallelogram ABCD ?  [#permalink]

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05 Apr 2011, 15:41
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What is the area of parallelogram ABCD ?

(1) AB = BC = CD = DA = 1
(2) AC = BD = $$\sqrt{2}$$

(C) 2008 GMAT Club - M13-05
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05 Apr 2011, 16:28
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Knesl wrote:
What is the area of parallelogram $$ABCD$$ ?

1. $$AB = BC = CD = DA = 1$$
2. $$AC = BD = \sqrt{2}$$

(C) 2008 GMAT Club - s10#1

* Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient
* Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient
* BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient
* EACH statement ALONE is sufficient
* Statements (1) and (2) TOGETHER are NOT sufficient

why is statement 2 not sufficient? when the two diagonals are to be the same then it is possible only in case of square. Therefore, the sides are defined as well. Or am I wrong?

1. Can be square or rhombus.

2.
Diagonals are same for rectangle and square.

For square the area will be:
Area = 1*1 as the side will be 1. Diagonal is $$sqrt{2}$$, Diagonal=hypotenuse of 45-90-45 right triangle. Side= 1.

For rectangle the sides can be:
0.5, 1.12; Area = 0.56
OR
0.75, 1.2; Area = 0.9

Basically, all combination of l and w that satisfies:
l^2+w^2=2. And there are infinite such possibilities.

Combining;
We know it's a square and area is 1.

Ans: "C"
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05 Apr 2011, 17:50
The answer is C as fluke has explained. To add a bit more, it were a square then there is no need to calculate the sides, the area can be simply 1/2 * d1 * d2.
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Re: What is the area of parallelogram ABCD ? 1. AB = BC = CD =  [#permalink]

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19 Mar 2014, 11:43
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I have a doubt in the explanation of this question. The official ans says that all four sides of parallelogram ABCD are equal, which implies that ABCD is a rhombus but this is the property of square(a parallelogram) as well...?\
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What is the area of parallelogram ABCD ?  [#permalink]

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20 Mar 2014, 01:56
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swati007 wrote:
I have a doubt in the explanation of this question. The official ans says that all four sides of parallelogram ABCD are equal, which implies that ABCD is a rhombus but this is the property of square(a parallelogram) as well...?

Yes, both a rhombus and a square have equal sides. From (1) we know that ABCD is a rhombus. A square is a special type of a rhombus, so from (1) ABCD is a rhombus and can be a square.

What is the area of parallelogram $$ABCD$$?

Notice that we are told that ABCD is a parallelogram.

(1) $$AB = BC =CD = DA = 1$$ --> all four sides of parallelogram ABCD are equal, which implies that ABCD is a rhombus. Area of a rhombus equals to $$\frac{d_1*d_2}{2}$$ (where $$d_1$$ and $$d_2$$ are the lengths of the diagonals) or $$bh$$ (where $$b$$ is the length of the base and $$h$$ is the altitude), so we don't have enough data to calculate the area. Not sufficient.

(2) $$AC = BD = \sqrt{2}$$ --> the diagonals of parallelogram ABCD are equal, which implies that ABCD is a rectangle. Area of a rectangle equals to length*width, so again we don't have enough data to calculate the area. Not sufficient. Notice that you cannot find the area of a rectangle just knowing the length of its diagonal.

(1)+(2) ABCD is a rectangle and a rhombus, so it's a square --> area=side^2=1^2=1. Sufficient.

Hope it's clear.
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Re: What is the area of parallelogram ABCD ? 1. AB = BC = CD =  [#permalink]

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17 Apr 2014, 07:16
Bunuel wrote:
swati007 wrote:
I have a doubt in the explanation of this question. The official ans says that all four sides of parallelogram ABCD are equal, which implies that ABCD is a rhombus but this is the property of square(a parallelogram) as well...?

Yes, both a rhombus and a square have equal sides. From (1) we know that ABCD is a rhombus. A rhombus is a special type of a square, so from (1) ABCD is a rhombus and can be a square.

What is the area of parallelogram $$ABCD$$?

Notice that we are told that ABCD is a parallelogram.

(1) $$AB = BC =CD = DA = 1$$ --> all four sides of parallelogram ABCD are equal, which implies that ABCD is a rhombus. Area of a rhombus equals to $$\frac{d_1*d_2}{2}$$ (where $$d_1$$ and $$d_2$$ are the lengths of the diagonals) or $$bh$$ (where $$b$$ is the length of the base and $$h$$ is the altitude), so we don't have enough data to calculate the area. Not sufficient.

(2) $$AC = BD = \sqrt{2}$$ --> the diagonals of parallelogram ABCD are equal, which implies that ABCD is a rectangle. Area of a rectangle equals to length*width, so again we don't have enough data to calculate the area. Not sufficient. Notice that you cannot find the area of a rectangle just knowing the length of its diagonal.

(1)+(2) ABCD is a rectangle and a rhombus, so it's a square --> area=side^2=1^2=1. Sufficient.

Hope it's clear.

HI Bunnel,

Diagonal of a square is also equals. then if both the diagonals are equal and root 2 then we have side as 1 and we can calculate the area.

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Re: What is the area of parallelogram ABCD ? 1. AB = BC = CD =  [#permalink]

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17 Apr 2014, 07:27
PathFinder007 wrote:
Bunuel wrote:
swati007 wrote:
I have a doubt in the explanation of this question. The official ans says that all four sides of parallelogram ABCD are equal, which implies that ABCD is a rhombus but this is the property of square(a parallelogram) as well...?

Yes, both a rhombus and a square have equal sides. From (1) we know that ABCD is a rhombus. A rhombus is a special type of a square, so from (1) ABCD is a rhombus and can be a square.

What is the area of parallelogram $$ABCD$$?

Notice that we are told that ABCD is a parallelogram.

(1) $$AB = BC =CD = DA = 1$$ --> all four sides of parallelogram ABCD are equal, which implies that ABCD is a rhombus. Area of a rhombus equals to $$\frac{d_1*d_2}{2}$$ (where $$d_1$$ and $$d_2$$ are the lengths of the diagonals) or $$bh$$ (where $$b$$ is the length of the base and $$h$$ is the altitude), so we don't have enough data to calculate the area. Not sufficient.

(2) $$AC = BD = \sqrt{2}$$ --> the diagonals of parallelogram ABCD are equal, which implies that ABCD is a rectangle. Area of a rectangle equals to length*width, so again we don't have enough data to calculate the area. Not sufficient. Notice that you cannot find the area of a rectangle just knowing the length of its diagonal.

(1)+(2) ABCD is a rectangle and a rhombus, so it's a square --> area=side^2=1^2=1. Sufficient.

Hope it's clear.

HI Bunnel,

Diagonal of a square is also equals. then if both the diagonals are equal and root 2 then we have side as 1 and we can calculate the area.

Please read the red part in my solution. Why should the sides equal to 1? Why cannot they be any numbers satisfying $$x^2+y^2=2$$?
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Re: What is the area of parallelogram ABCD ? 1. AB = BC = CD =  [#permalink]

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17 Apr 2014, 07:32
Bunuel wrote:
PathFinder007 wrote:
Bunuel wrote:

Yes, both a rhombus and a square have equal sides. From (1) we know that ABCD is a rhombus. A rhombus is a special type of a square, so from (1) ABCD is a rhombus and can be a square.

What is the area of parallelogram $$ABCD$$?

Notice that we are told that ABCD is a parallelogram.

(1) $$AB = BC =CD = DA = 1$$ --> all four sides of parallelogram ABCD are equal, which implies that ABCD is a rhombus. Area of a rhombus equals to $$\frac{d_1*d_2}{2}$$ (where $$d_1$$ and $$d_2$$ are the lengths of the diagonals) or $$bh$$ (where $$b$$ is the length of the base and $$h$$ is the altitude), so we don't have enough data to calculate the area. Not sufficient.

(2) $$AC = BD = \sqrt{2}$$ --> the diagonals of parallelogram ABCD are equal, which implies that ABCD is a rectangle. Area of a rectangle equals to length*width, so again we don't have enough data to calculate the area. Not sufficient. Notice that you cannot find the area of a rectangle just knowing the length of its diagonal.

(1)+(2) ABCD is a rectangle and a rhombus, so it's a square --> area=side^2=1^2=1. Sufficient.

Hope it's clear.

HI Bunnel,

Diagonal of a square is also equals. then if both the diagonals are equal and root 2 then we have side as 1 and we can calculate the area.

Please read the red part in my solution. Why should the sides equal to 1? Why cannot they be any numbers satisfying $$x^2+y^2=2$$?

For more on this trap check the following questions:
the-circular-base-of-an-above-ground-swimming-pool-lies-in-a-167645.html
figure-abcd-is-a-rectangle-with-sides-of-length-x-centimete-48899.html
in-right-triangle-abc-bc-is-the-hypotenuse-if-bc-is-13-and-163591.html
m22-73309-20.html
if-vertices-of-a-triangle-have-coordinates-2-2-3-2-and-82159-20.html
if-p-is-the-perimeter-of-rectangle-q-what-is-the-value-of-p-135832.html
if-the-diagonal-of-rectangle-z-is-d-and-the-perimeter-of-104205.html
what-is-the-area-of-rectangular-region-r-105414.html
what-is-the-perimeter-of-rectangle-r-96381.html
pythagorean-triples-131161.html
given-that-abcd-is-a-rectangle-is-the-area-of-triangle-abe-127051.html
m13-q5-69732-20.html#p1176059
m20-07-triangle-inside-a-circle-71559.html
what-is-the-perimeter-of-rectangle-r-96381.html
what-is-the-area-of-rectangular-region-r-166186.html
if-distinct-points-a-b-c-and-d-form-a-right-triangle-abc-129328.html

Hope this helps.
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Re: What is the area of parallelogram ABCD ? 1. AB = BC = CD =  [#permalink]

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17 Apr 2014, 08:01
Because diagonal of a square = site root2

now as it is given diagonals are equal and this is also property of a square . so if diagonal is root 2 then my site will be 1. and area of a square would be one.

Thanks
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Re: What is the area of parallelogram ABCD ? 1. AB = BC = CD =  [#permalink]

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17 Apr 2014, 08:28
PathFinder007 wrote:
Because diagonal of a square = site root2

now as it is given diagonals are equal and this is also property of a square . so if diagonal is root 2 then my site will be 1. and area of a square would be one.

Thanks

First of all from (2) we know that ABCD is a rectangle, not necessarily a square.

Next, the fact that the diagonals equals to $$\sqrt{2}$$ does not mean that the sides must be equal to 1. The sides can be:

$$\frac{1}{2}$$ and $$\frac{\sqrt{7}}{2}$$;
$$\frac{1}{3}$$ and $$\frac{\sqrt{7}}{\sqrt{3}}$$;
...

Basically the lengths of the sides can be any positive (x, y) satisfying $$x^2+y^2=(\sqrt{2})^2$$.

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Re: What is the area of parallelogram ABCD ? 1. AB = BC = CD =  [#permalink]

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17 Apr 2014, 10:41
Bunuel wrote:
PathFinder007 wrote:
Because diagonal of a square = site root2

now as it is given diagonals are equal and this is also property of a square . so if diagonal is root 2 then my site will be 1. and area of a square would be one.

Thanks

First of all from (2) we know that ABCD is a rectangle, not necessarily a square.

Next, the fact that the diagonals equals to $$\sqrt{2}$$ does not mean that the sides must be equal to 1. The sides can be:

$$\frac{1}{2}$$ and $$\frac{\sqrt{7}}{2}$$;
$$\frac{1}{3}$$ and $$\frac{\sqrt{7}}{\sqrt{3}}$$;
...

Basically the lengths of the sides can be any positive (x, y) satisfying $$x^2+y^2=(\sqrt{2})^2$$.

Clear. Thanks for your valuable input.
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What is the area of parallelogram ABCD ?  [#permalink]

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02 Feb 2015, 16:27
Knesl wrote:
What is the area of parallelogram ABCD ?

(1) AB = BC = CD = DA = 1
(2) AC = BD = $$\sqrt{2}$$

(C) 2008 GMAT Club - M13-05

Dear Bunuel, can we say - based on statement 2- that the parallelogram could be rhombus? If the answer is not can

you tell me why?
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Re: What is the area of parallelogram ABCD ?  [#permalink]

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03 Feb 2015, 03:35
23a2012 wrote:
Knesl wrote:
What is the area of parallelogram ABCD ?

(1) AB = BC = CD = DA = 1
(2) AC = BD = $$\sqrt{2}$$

(C) 2008 GMAT Club - M13-05

Dear Bunuel, can we say - based on statement 2- that the parallelogram could be rhombus? If the answer is not can

you tell me why?

From (2) we have that ABCD is a rectangle, and if it's a square, then it becomes a rhombus too.
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Re: What is the area of parallelogram ABCD ?  [#permalink]

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04 Feb 2015, 17:42
1
Bunuel wrote:
swati007 wrote:
I have a doubt in the explanation of this question. The official ans says that all four sides of parallelogram ABCD are equal, which implies that ABCD is a rhombus but this is the property of square(a parallelogram) as well...?

Yes, both a rhombus and a square have equal sides. From (1) we know that ABCD is a rhombus. A rhombus is a special type of a square, so from (1) ABCD is a rhombus and can be a square.

What is the area of parallelogram $$ABCD$$?

Notice that we are told that ABCD is a parallelogram.

(1) $$AB = BC =CD = DA = 1$$ --> all four sides of parallelogram ABCD are equal, which implies that ABCD is a rhombus. Area of a rhombus equals to $$\frac{d_1*d_2}{2}$$ (where $$d_1$$ and $$d_2$$ are the lengths of the diagonals) or $$bh$$ (where $$b$$ is the length of the base and $$h$$ is the altitude), so we don't have enough data to calculate the area. Not sufficient.

(2) $$AC = BD = \sqrt{2}$$ --> the diagonals of parallelogram ABCD are equal, which implies that ABCD is a rectangle. Area of a rectangle equals to length*width, so again we don't have enough data to calculate the area. Not sufficient. Notice that you cannot find the area of a rectangle just knowing the length of its diagonal.

(1)+(2) ABCD is a rectangle and a rhombus, so it's a square --> area=side^2=1^2=1. Sufficient.

Hope it's clear.

Thanks as always for your valuable and detailed explanations. However, you've mentioned that a 'rhombus is a special type of square', where as a square is a special type of rhombus. Parallelogram->Rectangle/Rhombus->Square.
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Re: What is the area of parallelogram ABCD ?  [#permalink]

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04 Feb 2015, 17:47
aviram wrote:
Bunuel wrote:
swati007 wrote:
I have a doubt in the explanation of this question. The official ans says that all four sides of parallelogram ABCD are equal, which implies that ABCD is a rhombus but this is the property of square(a parallelogram) as well...?

Yes, both a rhombus and a square have equal sides. From (1) we know that ABCD is a rhombus. A rhombus is a special type of a square, so from (1) ABCD is a rhombus and can be a square.

What is the area of parallelogram $$ABCD$$?

Notice that we are told that ABCD is a parallelogram.

(1) $$AB = BC =CD = DA = 1$$ --> all four sides of parallelogram ABCD are equal, which implies that ABCD is a rhombus. Area of a rhombus equals to $$\frac{d_1*d_2}{2}$$ (where $$d_1$$ and $$d_2$$ are the lengths of the diagonals) or $$bh$$ (where $$b$$ is the length of the base and $$h$$ is the altitude), so we don't have enough data to calculate the area. Not sufficient.

(2) $$AC = BD = \sqrt{2}$$ --> the diagonals of parallelogram ABCD are equal, which implies that ABCD is a rectangle. Area of a rectangle equals to length*width, so again we don't have enough data to calculate the area. Not sufficient. Notice that you cannot find the area of a rectangle just knowing the length of its diagonal.

(1)+(2) ABCD is a rectangle and a rhombus, so it's a square --> area=side^2=1^2=1. Sufficient.

Hope it's clear.

Thanks as always for your valuable and detailed explanations. However, you've mentioned that a 'rhombus is a special type of square', where as a square is a special type of rhombus. Parallelogram->Rectangle/Rhombus->Square.

Typo edited. Thank you.
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Re: What is the area of parallelogram ABCD ?  [#permalink]

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07 Sep 2017, 20:19
Knesl wrote:
What is the area of parallelogram ABCD ?

(1) AB = BC = CD = DA = 1
(2) AC = BD = $$\sqrt{2}$$

(C) 2008 GMAT Club - M13-05

Statement 1

Knowing htat the paralleogram has four equal sides is enough to determine that the figure is a rhombus since a rhombus is essentially an equilateral paralleogram. But we do not know the diagonal length of this rhombus and we cannot calculate the lengths of the diagonals with just the length of the sides. Insuff

Statement 2

Knowing that the parallelogram has two equal diagonals implies that the parallelogram is a rectangle... But what kind of rectangle? A square? If it we knew that that the parallelogram was a square then we could calculate the area of it by simply squaring the diagonal lengths and dividing by 2. Logically, a square IS a rhombus because the diagonals of a square can be squared and then divided by 2 in order to find the area.

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Re: What is the area of parallelogram ABCD ?  [#permalink]

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21 Mar 2019, 05:40
Bunuel wrote:
swati007 wrote:
I have a doubt in the explanation of this question. The official ans says that all four sides of parallelogram ABCD are equal, which implies that ABCD is a rhombus but this is the property of square(a parallelogram) as well...?

Yes, both a rhombus and a square have equal sides. From (1) we know that ABCD is a rhombus. A square is a special type of a rhombus, so from (1) ABCD is a rhombus and can be a square.

What is the area of parallelogram $$ABCD$$?

Notice that we are told that ABCD is a parallelogram.

(1) $$AB = BC =CD = DA = 1$$ --> all four sides of parallelogram ABCD are equal, which implies that ABCD is a rhombus. Area of a rhombus equals to $$\frac{d_1*d_2}{2}$$ (where $$d_1$$ and $$d_2$$ are the lengths of the diagonals) or $$bh$$ (where $$b$$ is the length of the base and $$h$$ is the altitude), so we don't have enough data to calculate the area. Not sufficient.

(2) $$AC = BD = \sqrt{2}$$ --> the diagonals of parallelogram ABCD are equal, which implies that ABCD is a rectangle. Area of a rectangle equals to length*width, so again we don't have enough data to calculate the area. Not sufficient. Notice that you cannot find the area of a rectangle just knowing the length of its diagonal.

(1)+(2) ABCD is a rectangle and a rhombus, so it's a square --> area=side^2=1^2=1. Sufficient.

Hope it's clear.

Bunnel can u plz explaon why 2nd statement alone is not sufficient ?
Re: What is the area of parallelogram ABCD ?   [#permalink] 21 Mar 2019, 05:40
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